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Escape velocity is the speed required to?
escape the gravitational well and if the planetoid has one, the atmosphere.
What is Rocket speed per sec to escape from earth gravity?
the rocket speed required to escape out of the earth's gravity is known as escape velocity which is numerically equal to 11.2 km per sec.
What are the release dates for Escape Velocity - 1999?
Escape Velocity - 1999 was released on: USA: 28 November 1999 (video premiere) UK: 14 October 2002 France: November 2005
What are the release dates for Battlestar Galactica - 2004 Escape Velocity - 4.4?
Battlestar Galactica - 2004 Escape Velocity - 4.4 was released on: USA:25 April 2008 UK:29 April 2008 Spain:23 October 2008 Germany:6 December 2008 (limited) Hungary:13 October 2009 (DVD premiere) Japan:10 March 2010 Germany:24 March 2010 Netherlands:26 January 2011 Finland:28 May 2011
What are the lyrics to Nuku Te Aio?
Nei te iti oNgati Raukawa, Te Atiawa, Toa RangatiraE whakamanawa atu nei ki aku rau rangatiraNuku te Aio, Nuku te Aio, Nuku te Aio, Nuku te Aio.Ka mihi ki nga manaakitanga I uwhia mai ai e koutou.Me wai manawhenua te hohonuNei te whakahoki atu nei I te hau uuu ko te whakaaroNuku te Aio, Nuku te Aio, Nuku te Aio, Nuku te Aio
What is the formula for deriving escape velocity from a celestial body?
The formula for calculating escape velocity from a celestial body is v (2GM/r), where v is the escape velocity, G is the gravitational constant, M is the mass of the celestial body, and r is the distance from the center of the body to the point where the escape velocity is being calculated.
How can one determine how to find escape velocity in a given scenario?
To find escape velocity in a given scenario, you can use the formula: escape velocity square root of (2 gravitational constant mass of the planet / radius of the planet). This formula takes into account the gravitational pull of the planet and the mass and radius of the planet. By plugging in these values, you can calculate the escape velocity needed to leave the planet's gravitational pull.
How can one derive the escape velocity of an object from a celestial body?
To derive the escape velocity of an object from a celestial body, you can use the formula: escape velocity (2 gravitational constant mass of celestial body / distance from the center of the celestial body). This formula takes into account the gravitational pull of the celestial body and the distance of the object from its center. By calculating this value, you can determine the minimum velocity needed for an object to escape the gravitational pull of the celestial body.
What is the escape velocity from an asteroid with mass 3000 gm and radius of 10 m?
The escape velocity from an asteroid can be calculated using the formula: escape velocity = sqrt(2 * gravitational constant * mass of asteroid / radius of asteroid). Substituting the given values, the escape velocity from the asteroid would be approximately 200 m/s.
What escape velocity of a particle of mass m varies as?
The escape velocity of a particle of mass m is independent of the mass of the particle. It is solely dependent on the mass and radius of the object it is trying to escape from. The escape velocity is given by the formula: (v = \sqrt{\frac{2GM}{r}}), where G is the gravitational constant, M is the mass of the object, and r is the distance from the center of the object to the particle.
When did Escape Velocity Override happen?
Escape Velocity Override happened in 1998.
When was Escape Velocity Override created?
Escape Velocity Override was created in 1998.
When did Escape Velocity Nova happen?
Escape Velocity Nova happened in 2002.
When was Escape Velocity - Doctor Who - created?
Escape Velocity - Doctor Who - was created in 2001.
What is the escape velocity of the asteroid belt?
Each asteroid has its own escape velocity.
Is escape velocity same for all objects?
Yes. It is different for different planets etc. Escape velocity on earth is different than escape velocity on Jupiter.
What is escape velocity of speed?
You mean what is the escape velocity of Earth? If so, the answer is 11,2 km/s
