The factors of 210 are:
1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70, 105, 210
The factors of 315 are:
1, 3, 5, 7, 9, 15, 21, 35, 45, 63, 105, 315
The factors of 735 are:
1, 3, 5, 7, 15, 21, 35, 49, 105, 147, 245, 735
The common factors are:
1, 3, 5, 7, 15, 21, 35, 105
The Greatest Common Factor (GCF) is:
105
The gcf is 105
The GCF is 35.
Here are some multiples of both 15 and 7: 105, 210, 315, 420, 525, 630, 735, 840, 945.
315 = 32 x 5 x 7525 = 3 x 5 x 73 x 5 x 7 = 105 (GCF)
210 and 420 have a GCF of 210.
The GCF is 105.
The GCF is: 105
105.
The GCF of 210 and 735 is 105. This leaves you with 2 and 7. There are no further divisible numbers in common (aside from 1).
The gcf is 105
The GCF is 35.
105, 210, 315, 420, 525, 630, 735, 840, 945 . . .
105, 210, 315, 420, 525, 630, 735 +105 . . .
The list is infinite. Here are some of them: 210, 315, 420, 525, 630, 735, 840.
The GCF is 105.
Here are some multiples of both 15 and 7: 105, 210, 315, 420, 525, 630, 735, 840, 945.
This is a slight twist to the normal find the GCF of two numbers. In this case as a remainder of 7 is required, subtracting 7 from each number and then finding the GCF of the resulting numbers will solve the problem: 742 - 7 = 735 1162 - 7 = 1155 GCF of 1155 and 735 (using Euclid's method): 1155 / 735 = 1 r 420 735 / 420 = 1 r 315 420 / 315 = 1 r 105 315 / 105 = 3 r 0 GCF of 735 & 1155 is 105, thus 105 is the greatest number that will divide 742 and 1162 leaving a remainder of exactly 7 each time.