2 x 7 = 14
3 x 7 = 21
2 x 3 x 7 = 42, the LCM
The GCF of 14, 31, 39, and 56 is 1. One way to solve the problem is to notice that 31 is prime, and can't possibly be a factor of 14, which is smaller.If you prefer, you can write the prime factorization of each number in the set and find the GCF:The prime factorization of 14 is 2*7The prime factorization of 31 is 31 (1*31)The prime factorization of 39 is 3*39The prime factorization of 56 is 2*2*2*7So the GCF is 1.
You can't find an LCM or a CF of a single number. You need at least two. The prime factorization of 71421 is 3 x 7 x 19 x 179 If you're asking about 7, 14 and 21, the LCM is 42 and the CF are 1 and 7 7 2 x 7 3 x 7
The LCM is 1,890
2 x 7 = 14 3 x 7 = 21 2 x 2 x 7 = 28 2 x 2 x 3 x 7 = 84, the LCM If you got 168, you didn't eliminate the 2 from 14.
The Least Common Multiple (LCM) of 7 and 14 is 14.
2 x 7 = 14 7 x 7 = 49 2 x 7 x 7 = 98, the LCM
No prime power exists since there are no duplicate prime numbers in the prime factorization.
The LCM of 14 and 24 is 168.The prime factorization of 14 is 2 x 7;The prime factorization of 24 is 2 x 2 x 2 x 3,Their only common factor is 2 so LCM = 168168
182 Prime Factorization of: 14 =...2 * 7 26 =...2 .....* 13 =========== LCM= 2 * 7 * 13 = 182
It is: 21*71 = 14
2 x 2 x 2 = 8 2 x 7 = 14 2 x 2 x 2 x 7 = 56, the LCM
14 = 21 x 71
It is: 2*7 = 14 and no exponents are needed
lcm(7, 12, 14) = 84 Using prime factorization: 7 = 7 12 = 2² x 3 14 = 2 x 7 lcm = 2² x 3 x 7 = 84
If your asking what is the prime factorization of 14: 2 times 7
Using the prime factors of 14 and 6, the LCM is 42 (2 x 3 x 7).
it is 14