2 x 7 = 14
3 x 7 = 21
2 x 3 x 7 = 42, the LCM
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∙ 11y agoThe greatest common factor of 12, 18, and 28 is 2.The prime factorization of 12 is 2*2*3The prime factorization of 18 is 2*3*3The prime factorization of 28 is 2*2*7So the greatest common factor of the set is 2.
The GCF of 14, 31, 39, and 56 is 1. One way to solve the problem is to notice that 31 is prime, and can't possibly be a factor of 14, which is smaller.If you prefer, you can write the prime factorization of each number in the set and find the GCF:The prime factorization of 14 is 2*7The prime factorization of 31 is 31 (1*31)The prime factorization of 39 is 3*39The prime factorization of 56 is 2*2*2*7So the GCF is 1.
The LCM is 1,890
You can't find an LCM or a CF of a single number. You need at least two. The prime factorization of 71421 is 3 x 7 x 19 x 179 If you're asking about 7, 14 and 21, the LCM is 42 and the CF are 1 and 7 7 2 x 7 3 x 7
2 x 7 = 14 3 x 7 = 21 2 x 2 x 7 = 28 2 x 2 x 3 x 7 = 84, the LCM If you got 168, you didn't eliminate the 2 from 14.
2 x 7 = 14 7 x 7 = 49 2 x 7 x 7 = 98, the LCM
No prime power exists since there are no duplicate prime numbers in the prime factorization.
It is: 21*71 = 14
The LCM of 14 and 24 is 168.The prime factorization of 14 is 2 x 7;The prime factorization of 24 is 2 x 2 x 2 x 3,Their only common factor is 2 so LCM = 168168
182 Prime Factorization of: 14 =...2 * 7 26 =...2 .....* 13 =========== LCM= 2 * 7 * 13 = 182
2 x 2 x 2 = 8 2 x 7 = 14 2 x 2 x 2 x 7 = 56, the LCM
14 = 21 x 71
It is: 2*7 = 14 and no exponents are needed
lcm(7, 12, 14) = 84 Using prime factorization: 7 = 7 12 = 2² x 3 14 = 2 x 7 lcm = 2² x 3 x 7 = 84
If your asking what is the prime factorization of 14: 2 times 7
it is 14
Using the prime factors of 14 and 6, the LCM is 42 (2 x 3 x 7).