What is the factors of 4wt plus 2wh plus 6it plus 3ih?

Answer 1

There are four terms in the expression: 4wt, 2wh, 6it and 3ih.

4wt and 2wh have 2w in common and 6it and 3ih have 3i in common.

4wt + 2wh can be written as 2w(t + h) and 6it + 3ih can be written as 3i(t + h).

So the whole algerbraic expression can be written as:

2w(t + h) + 3i(t + h)

Now consider that 2w(t + h) and 3i(t + h) are two new terms and both have (t + h) in common.

Rewriting the expression we get:

(2w + 3i)(t + h).

So, the required factors are (2w + 3i) and (t + h).