There is no such number. Once you have one n-digit number which is divisible by 4 then 10 times that number will be an n+1 digit number which is divisible by 4. And this process can continue ad infinitum.
Chat with our AI personalities
To work this out, first write down the greatest 4 digit number
9999
then divide this by 12
9999/12 = 833.25
Take the number before the decimal point (833) and multiply this by 12
833*12 = 9996
9996 is the greatest four digit number that is divisible by 12.
It would have been easier if you had specified how many digits you wanted, but every number that ends in 96 is divisible by 4. Just add as many nines as you need in front of the 96.
If a number is divisible by both three and four, it's divisible by twelve.
Take the number 3336. You know it's divisible by 1 because everything is. You know it's divisible by 2 because it's even. You know it's divisible by 3 because the digits add up to a multiple of 3 and you know it's divisible by 4 because the last two digits are divisible by 4. So you've found at least four factors: 1,2,3 and 4.
If it's to be divisible by 5, it must end in 5 or 0. And if it's to be divisible by 3, adding the digits together must result in a multiple of 3.While some numbers that end in zero will still work, you can guarantee that the number won't be divisible by four by choosing a number that ends in five.So you'd need a four-digit number, that ends in 5, whose digits add up to a multiple of 3. The smallest such number would be 1005, and the largest would be 9975.(However, the actual largest number that would fit your question is 9990; remember that I did say some numbers that end in zero would still work.)
18, 24, 32, 36
No. Four is not evenly divisible by 25.