If there is a remainder of 2 then number will divide 2 less than 110 (= 108) and 128 (=126) and be the largest such number. Thus need the hcf of 108 and 126:
108 = 22 x 33
126 = 2 x 32 x 7
hcf = 2 x 32 = 18
Thus 18 is the greatest number which will divide 110 and 128 with a remainder of 2 in each case.
9 is the largest integer that can divide into both 36 and 81 evenly with no remainder.
The greatest common factor (GCF) of 8, 10, and 14 is 2. To find the GCF, you need to determine the largest number that can evenly divide all three numbers. In this case, 2 is the largest number that can divide 8, 10, and 14 without leaving a remainder, making it the greatest common factor.
That's a misrepresentation of the term "greatest common factor," or GCF, which is the largest number that will divide evenly with no remainder into all the members of a set of two or more given numbers.
No. 3 is. The highest common factor is the highest number that will divide into both numbers without leaving a remainder
The largest number that will divide into 28 42 and 70 with no remainder is 14.
If you're dividing a whole number by 2, then the greatest possible remainder is 1.
7.
22
When a number can be divided by another number without leaving a remainder, it is called divisible. For example, 10 is divisible by 2 because when we divide 10 by 2, there is no remainder.
It is: 40
It is 22.
40
To find the greatest number that will divide 11296 and leave a remainder of 11, we need to use the concept of divisors. The number that satisfies this condition is called the Greatest Common Divisor (GCD). By using the Euclidean algorithm, we can find that the GCD of 11296 and 11 is 1. Therefore, the greatest number that will divide 11296 and leave a remainder of 11 is 1.
It is: 46
A factor or a divisor is a number that will divide into another number evenly and leaving no remainder.
The greatest possible remainder for 76 is to be divided by 2 leaving the result of 38. Thank you!
1, any number that you divide by 2 is either divisible by 2 (even) or not divisible by 2, leaving a remainder of 1 (odd).