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12 = 2*2*3

28 = 2*2*7

35 = 5*7

In the above factorisations:

The factor 2 appears at most twice

The factor 3 appears at most once

The factor 5 appears at most once

The factor 7 appears at most once

So LCM = 2*2*3*5*7 = 420

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βˆ™ 12y ago
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βˆ™ 8y ago

The LCM of 12, 28 and 35 is 420.

2 x 2 x 3 = 12

2 x 2 x 7 = 28

5 x 7 = 35

Combine the highest amount of each factor.

2 x 2 x 3 x 5 x 7 = 420, the LCM

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βˆ™ 11y ago

The least common factor is 1. (The least common factor of any two or more positive integers is always 1.)

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Q: What is the least common factor of 35 and 28?
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