It is not possible to express something as a sum of whole numbers with no common factor. All whole numbers have at least 1 as a common factor.
Any multiple of 35, like 280.
Common three-digit multiples of 27 and 11 are 297, 594 and 891. None of their digits add up to 10.
Numbers for which the sum of the digits is divisible by 9. This is also true for 3. There are other divisibility/multiple tests for other numbers (e.g., numbers that are divisible by 5 end in 5 or 0; numbers whose last two digits are divisible by 4 are divisible by 4)
If you compare 36 to any other even number, they will have at least 1 and 2 in common.
Answer: 276
3, 15 and 20
12 and 20
36 and 60.
45 and 10
20 and 24
This question makes no sense whatsoever. The world "least" is a superlative term. That means there can be only one such number. So two numbers cannot be LCMs in the same scenario. Next, the least "common" multiple (LCM) refers to a multiple that is COMMON to two or more numbers. You have only one number, 48, in the question! The least common multiple of 48 and some other number must be at least as great as 48 and so two numbers - if they could exist, would have a sum of at least 48 + 48 = 96. You need to read up on LCM
try 45 and 10 maybe?
12 and 20
=The two numbers to this question are 40 and 50.=
It is not possible to express something as a sum of whole numbers with no common factor. All whole numbers have at least 1 as a common factor.
The answer is: 3