They are members of an infinite set of numbers of the form 10000*k where k is an integer.
They are the common multiples of the two numbers.
The multiples of 246 and 12 are 492 and all the multiples of 492.
All numbers have an infinite amount of multiples.
Four has an infinite number of multiples.
There are no multiples of 500 in 100.
None.
3,333.
There are 3,333 multiples of three that fall between 1 and 10,000.
Only the multiples of 1000.
They are the 3333 numbers that are divisible by 3 without remainder.
10000, 20000, 30000, 40000, 50000, 60000, 70000.
2000, 4000, 6000, 8000, 10000, 12000, 14000, 16000, . . .
This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858
1 time all other occasion there are multiples of nine (9)
1000, 2000, 3000, 4000, 5000, 6000, 7000, 8000, 9000, 10000, 11000, . . .
10000
10000 10000 10000 10000 10000