These factor pairs, when multiplied, equal 273: (1, 273) (3, 91) (7, 39) (13, 21)
35 can be a factor, but it is not prime.
81 is not prime. Its prime factorization is 3x3x3x3.
There is no factorization. 37 is a prime number.37 is already prime. Its only prime factor is itself.
Each of these factor pairs (multiply the numbers in parentheses) equals 273: (1, 273) (3, 91) (7, 39) (13, 21)
13
273 91,3 13,7,3
Yes, since their highest common factor is one.
273 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 8 factors of 273 are 1, 3, 7, 13, 21, 39, 91, and 273.The factor pairs of 273 are 1 x 273, 3 x 91, 7 x 39, and 13 x 21.The proper factors of 273 are 1, 3, 7, 13, 21, 39, and 91 or,if the definition you are using excludes 1, they are 3, 7, 13, 21, 39, and 91.The prime factors of 273 are 3, 7, and 13.The 3 distinct prime factors (listing each prime factor only once) of 273 are 3, 7, and 13.The prime factorization of 273 is 3 x 7 x 13.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
13 is a factor of 273. The number you multiply 13 by to get 273 is 21.
273 / \ 91x3 /\ \ 13x7x3
The greatest common factor of 266 and 273 is 7.
The prime factorization of 27 is 3 X 3 X 3. In exponential form it is 3 cubed.Here is a factor tree:273 x 93 x 3 x 33 x 3 x 3
No, 273 is not a prime number. It is a composite number. A prime number can only be divided by 1 and itself. 273 can also be divided by 3, 7, 13, 21, 39, and 91.
sicne 13 is prime it simple is 13*21=273 or you can factor it as well and see 13=1*13 21=3*7 LCM=3*7*13=273
Highest common factor of 273 and 315 is 21.
273 = 3 x 7 x 13