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2 x 2 x 3 x 3 x 5 = 180
2 x 3 x 3 x 5 x 5 = 450
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Is there a direct way to determine the number of positive factors that a given number like 1800 has?
The easiest way is through easy websites such as this: http://wiki.answers.com/Q/What_are_the_factors_of_mathAlternatively, you can use prime factorization. In this case, 1800 = 2*2*2*3*3*5*5. Thus any divisor contains at most three factors of 2;that means there are four possibilities: 0, 1, 2, or 3 factors of 2. Similarly there are three possibilities for the number of factors of 3 in a divisor, and the same for factors of 5. Multiplying these together, we find there are 4*3*3 = 36 positive integer divisors of 1800.In general, take the exponents in the prime factorization, add one to each of them, and multiply the resulting numbers together.
Who was the british prime minister in the late 1800s?
William Pitt The Younger was prime minister in 1800. In the late 1800s it was Robert Gascoyne-Cecil.
When was ET born?
he is part of a alien race from a galaxy far away. he is 500 years old, the prime age of that species. they go on to live for up to 1800 years old
Who was a British prime ninister in the late 1800?
Lord Liverpool who held office continuously for 15 years, but was not too popular.
If its 1800 hrs PDT what time is it in MST?
1800 hrs PDT = 1800 hrs MST.
What numbers prime factorization is 2x2x2x3x3x5x5?
The prime factorization of 1800 is 2x2x2x3x3x5x5
What number has the prime factorization is 2x2x2x3x3x5x5?
It is: 1800
What are the prime factors of 1800?
The prime factorization of 1800 is 2 * 2 * 2 * 3 * 3 * 5 * 5, so the prime factors of 1800 are 2, 3 and 5
What is the prime factorization of 1800 in the factor tree?
highest common factor of 490 and 1`750
What number has the prime factorization 2223355?
2 * 2 * 2 * 3 * 3 * 5 * 5 = 1800
What number has the prime factorization 23x32x52?
Assuming that's 23 x 32 x 52, that multiplies to 1800.
What is the exponent of 1 800?
As a product of its prime factors in exponents: 23*32*52 = 1800 Or expressed in scientific notation: 1.8*103
What number has the prime factorization 2x2x2x5x5x9 Show us how you found that number?
Multiplying all these prime factors together (this sum can be simplified to 23x52x9) gives us 1800.
What number has the prime factorization of 2 to the third power times three to the second power times five to the second power?
1800
What number has the prime factorization 2to the 3rd power 3 to the 2nd power 5 to the 2nd power?
23 x 32 x 52 = 1800
What is the Prime Factorization of 900 times 2?
2 x 2 x 2 x 3 x 3 x 5 x 5 = 1800
Is there a direct way to determine the number of positive factors that a given number like 1800 has?
The easiest way is through easy websites such as this: http://wiki.answers.com/Q/What_are_the_factors_of_mathAlternatively, you can use prime factorization. In this case, 1800 = 2*2*2*3*3*5*5. Thus any divisor contains at most three factors of 2;that means there are four possibilities: 0, 1, 2, or 3 factors of 2. Similarly there are three possibilities for the number of factors of 3 in a divisor, and the same for factors of 5. Multiplying these together, we find there are 4*3*3 = 36 positive integer divisors of 1800.In general, take the exponents in the prime factorization, add one to each of them, and multiply the resulting numbers together.
