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The prime factorization of 1800 can be found by breaking it down into its prime factors: 2 x 2 x 2 x 3 x 3 x 5 x 5. This can be written in exponential form as 2^3 x 3^2 x 5^2. This means that 1800 can be expressed as the product of these prime numbers raised to their respective exponents.
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Is there a direct way to determine the number of positive factors that a given number like 1800 has?
The easiest way is through easy websites such as this: http://wiki.answers.com/Q/What_are_the_factors_of_mathAlternatively, you can use prime factorization. In this case, 1800 = 2*2*2*3*3*5*5. Thus any divisor contains at most three factors of 2;that means there are four possibilities: 0, 1, 2, or 3 factors of 2. Similarly there are three possibilities for the number of factors of 3 in a divisor, and the same for factors of 5. Multiplying these together, we find there are 4*3*3 = 36 positive integer divisors of 1800.In general, take the exponents in the prime factorization, add one to each of them, and multiply the resulting numbers together.
Who was the british prime minister in the late 1800s?
William Pitt The Younger was prime minister in 1800. In the late 1800s it was Robert Gascoyne-Cecil.
When was ET born?
he is part of a alien race from a galaxy far away. he is 500 years old, the prime age of that species. they go on to live for up to 1800 years old
Who was a British prime ninister in the late 1800?
Lord Liverpool who held office continuously for 15 years, but was not too popular.
If its 1800 hrs PDT what time is it in MST?
1800 hrs PDT = 1800 hrs MST.
