Any multiple of 35, like 280.
91
the first three common multiples of 7, 20, and 35 are 140, 280, and 420
Any multiple of 14.They are members of the infinite set of numbers of the form 14*k where k is an integer. Since the set is infinite, it is not possible to list them.
The first 3 multiples of 7 are: 7, 14, and 21.The first 3 multiples of 14 are: 14, 28, and 42.
5 + 10+15+20=50 ans
-5
The first 2 multiples are 42,84.
This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858
lcm(2, 7) = 14 → first 3 common multiples are: 14, 28, 42; lcm(2, 8) = 8 → first 3 common multiples are: 8, 16, 24; lcm(7, 8) = 56 → first 3 common multiples are: 56, 112, 168; lcm(2, 7, 8) = 56 → first 3 common multiples are: 56, 112, 168.
2
These are the first 90 multiples of 7:714212835424956637077849198105112119126133140147154161168175182189196203210217224231238245152159266273280287294301308315322329336343350357364371378385392399406413420427434441448455462469476483490497504511518525532539546553560567574581588595602609616623630
The first 3 multiples of 7 are: 7, 14, and 21.
Sum of first 7 prime numbers is equal to 2+3+5+7+11+13+17 = 58.
14, 28, 42
168, 336, 504
14, 28, 42