If p is any Prime number, then p12 would meet the requirements. The seven factor pairs would be:
(p0, p12)
(p1, p11)
(p2, p10)
(p3, p9)
(p4, p8)
(p5, p7)
(p6, p6)
It can be shown that, because 7 is a prime, a composite number cannot generate such a solution.
(1, 21) (3, 7)
There are 3 factor pairs of 245:245 = 1 x 245245 = 5 x 49245 = 7 x 35
The factor pairs for 77 are (1,77) and (7,11).
They are: 1, 2, 7 and 14
14 and 21, and 21 and 28 are the number pairs between 15 and 30 that have 7 as their greatest common factor.
1 and 7
1 and 14, 2 and 7
Its factors are only itself and one because 7 is a prime number
1 and 7
The factor pairs of 14 are 1*14, and 2*7
14 = 1*14, 2*7 14 = 1 x 14 ( 1st factor pairs) = 2 x 7 (2nd factor pairs
The factor pairs of 28 are 1*28, 2*14, and 4*7
The factor pairs of 168 are the pairs of numbers that can be multiplied together to give the product 168. These pairs include (1, 168), (2, 84), (3, 56), (4, 42), (6, 28), (7, 24), (8, 21), and (12, 14). Factors are numbers that divide evenly into a given number, and in the case of 168, these factor pairs represent all the possible combinations of factors that multiply to 168.
There are 3 factor pairs of 63: 63 = 1 x 63 63 = 3 x 21 63 = 7 x 9
1 and 7
Factors of 21 are 1, 3, 7, and 21; the factor pairs are (1 x 21) and (3 x 7).
1 x 7, 7 x 1