If p is any Prime number, then p12 would meet the requirements. The seven factor pairs would be:
(p0, p12)
(p1, p11)
(p2, p10)
(p3, p9)
(p4, p8)
(p5, p7)
(p6, p6)
It can be shown that, because 7 is a prime, a composite number cannot generate such a solution.
(1, 21) (3, 7)
There are 3 factor pairs of 245:245 = 1 x 245245 = 5 x 49245 = 7 x 35
The factor pairs for 77 are (1,77) and (7,11).
They are: 1, 2, 7 and 14
14 and 21, and 21 and 28 are the number pairs between 15 and 30 that have 7 as their greatest common factor.
1 and 7
1 and 14, 2 and 7
Its factors are only itself and one because 7 is a prime number
1 and 7
The factor pairs of 14 are 1*14, and 2*7
14 = 1*14, 2*7 14 = 1 x 14 ( 1st factor pairs) = 2 x 7 (2nd factor pairs
Try to factor this number. Look for small factors first - numbers like 2, 3, 5, 7. That is, try whether your number is divisible by such numbers. Once you find such a factor, divide the number by your factor to get the other factor.
There are 3 factor pairs of 63: 63 = 1 x 63 63 = 3 x 21 63 = 7 x 9
The factor pairs of 28 are 1*28, 2*14, and 4*7
1 and 7
Factors of 21 are 1, 3, 7, and 21; the factor pairs are (1 x 21) and (3 x 7).
1 x 7, 7 x 1