These numbers: 1, 2, 4, 13, 26, 52.
1,2,4,13,26,52
Each of these factor pairs (multiply the numbers in parentheses) equals 52: (1, 52) (2, 26) (4, 13)
The least common multiple of the numbers 90 and 52 is 2,340.
You need at least two numbers to find a GCF.
These numbers go evenly into 52: 1, 2, 4, 13, 26, 52.
you press: o=52 y=56
52
52=2x2x13
Well, darling, numbers divisible by 52 are any multiples of 52. So, you've got 52, 104, 156, and so on. Just take 52 and keep adding 52 to it, and you've got yourself a whole bunch of numbers divisible by 52. Math made easy, honey!
Neither 27 nor 52 are prime numbers. Both are composite numbers, instead.
They are 39 and 52.
This questions can be rewritten as 52 choose 6 or 52C6. This is the same as (52!)/(6!(52-6)!) (52!)(6!46!) (52*51*50*49*48*47)/(6*5*4*3*2*1) 14658134400/720 20358520 There are 20,358,520 combinations of 6 numbers in 52 numbers. This treats 1,2,3,4,5,6 and 6,5,4,3,2,1 as the same combination since they are the same set of numbers.
23 + 29 = 52
23 + 29 = 52
These numbers: 1, 2, 4, 13, 26, 52.
There are 52/2=26 even numbers in 52. Hence there are 26 odd numbers in 52, since 1 the first number is odd. You also get 26 if you count them: 1,3,5, ... 51.