The HCF of the given three numbers is 9 and because the digital sum of the given numbers equals 9 then the numbers are all divisible by 9
-113
The numbers are 4 and 13
3³ = 3 x 3 x 3 = 27 1 x 3 x 9 = 27 1 x 1 x 27 = 27
The factors of 9 are 1, 3, and 9, as these are the numbers that can be multiplied together to give the product of 9. The factors of 27 are 1, 3, 9, and 27, as these are the numbers that can be multiplied together to give the product of 27. In both cases, the factors are the numbers that evenly divide into the given number without leaving a remainder.
29
-19
9, 18 and 36
-9+4
-49
The numbers are: -9 and 24
They are: 3+2 = 5 and 3^2 = 9
16
-25
25
-41
The two numbers that add to 16 and multiply to 63 are 7 and 9. This is because 7 + 9 = 16 and 7 * 9 = 63. These numbers satisfy both conditions simultaneously, making them the correct solution to the problem.