The HCF of the given three numbers is 9 and because the digital sum of the given numbers equals 9 then the numbers are all divisible by 9
-113
The numbers are 4 and 13
3³ = 3 x 3 x 3 = 27 1 x 3 x 9 = 27 1 x 1 x 27 = 27
The numbers below are the factor pairs of 567 (multiplied together they equal 567) (1, 567) (3, 189) (7, 81) (9, 63) (21, 27)
29
-19
9, 18 and 36
The two numbers that add to 16 and multiply to 63 are 7 and 9. This is because 7 + 9 = 16 and 7 * 9 = 63. These numbers satisfy both conditions simultaneously, making them the correct solution to the problem.
-9+4
-49
The numbers are: -9 and 24
They are: 3+2 = 5 and 3^2 = 9
16
-25
25
-41