Both 10 and 20 are two-digit numbers that are factors of 20.
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20 - 1,2,4,5,10,20 You can not have a GCF of just one number. But written are the factors of 20.
The greatest common factor of 12 and 20 is 4
The highest factor of any number is the number itself. The GCF of 20 and 50 is 10.
Factor pairs are any two numbers being multiplied to give you a certain number. Examples for 20: 1x20, 20x1, 2x10, 10x2, 4x5, and 5x4 are all factor pairs for 20.
yes you do because 5 is a factor of 20 and so is 2 and 5x2=10 and 10 is a factor of 20
10, 20, 25, 50
10, 20, 25, 50
2*10=20
20.
21 and 20
There cannot be a proper three digit number between 10 and 20. It must be a two digit number. If you consider a 2-digit number between 10 and 20, then its tens digit MUST be 1 and so MUST be odd. So most of this question is either wrong or irrelevant. Are you sure you have not cut and pasted bits from two questions?
No. When adding the smallest 2 digit number (= 10) to the smallest 2 digit number (again, 10) the result is a 2 digit number (10 + 10 = 20). When adding the largest 2 digit number (= 99) to the largest 2 digit number (again, 99) the result is a 3 digit number (99 + 99 = 198). As you can see, you'll either get a 2 or 3 digit number, but never a 4 digit number.
1/20 = 5%
12
There cannot be a common factor of just one number. To be common there need to be at least two numbers.
The two number are coprime: their common factor is 1.
To find the number of 5-digit combinations from 1 to 20, we first calculate the total number of options for each digit position. Since the range is from 1 to 20, there are 20 options for the first digit, 20 options for the second digit, and so on. Therefore, the total number of 5-digit combinations is calculated by multiplying these options together: 20 x 20 x 20 x 20 x 20 = 3,200,000 combinations.