110
The factors of 35 are 1, 5, 7, and 35. There are only two factors with a difference of 2; they are 5 and 7. 1 and 5 have a difference of 4. 1 and 7 have a difference of 6. 1 and 35 have a difference of 34. 5 and 7 have a difference of 2. 5 and 35 have a difference of 30. 7 and 35 have a difference of 28.
They are 6 and 8
The factors of 56 are: 1, 2, 4, 7, 8, and 56. The prime factors are 2 and 7. Not sure what is being asked as far as the difference in the factors since there are more than two. If you only use two numbers to get 56 they would have to be 7 and 8. The difference then being 1.
Two.
To find the factors of 560 where the middle term is -24, we can express the equation in the form of (x^2 + mx + n = 0), where (m) is the middle term and (n) is the product of the factors. The factors of 560 that also add up to -24 are -14 and -40, since (-14 + (-40) = -24) and (-14 \times -40 = 560). Thus, the required factors are -14 and -40.
7 and 14, or 49 and 2.
-14 and -14 Add them together to get -28 Multiply them to get 196
25 and 11
The factors of 35 are 1, 5, 7, and 35. There are only two factors with a difference of 2; they are 5 and 7. 1 and 5 have a difference of 4. 1 and 7 have a difference of 6. 1 and 35 have a difference of 34. 5 and 7 have a difference of 2. 5 and 35 have a difference of 30. 7 and 35 have a difference of 28.
9 and 5
No, it does not.
The factors of -84 that equal the sum of -16 are: -28 and 12 -14 and -2 -12 and -4
45
404
2 and 14
They are 6 and 8
No 7 is a prime number and only has the trivial factors 1 and 7. The factors of 14 are : 14, 7, 2, and 1. Two is therefore a factor of 14.