Taking the two cons. evens to be 2n & 2n + 2, and using
product of two given numbers = their LCM x their gcf, we come up with
4n(n+1) = 120, or n(n+1) = 30, leading to n = 5. The two cons. even nos. in the question turn out to be 10 & 12.
This doesn't work. The LCM of a pair of numbers has to be equal to or larger than the largest number of the pair. If one of the numbers is 60, the other is 120. 60 and 120 have a GCF of 60, not an LCM.
You need at least two numbers to find an LCM.
You need at least two numbers to find an LCM.
The least common multiple (LCM) of two numbers is the smallest number that is a multiple of both numbers. To find the two numbers with an LCM of 1260, we need to factorize 1260 into its prime factors, which are 2, 2, 3, 3, 5, and 7. We then pair these prime factors to form two numbers, such as 2 x 2 x 3 x 5 = 60 and 3 x 7 = 21. Therefore, the two numbers with an LCM of 1260 are 60 and 21.
You must have at least 2 numbers to have a LCM. If you mean 30 and 42... LCM = 5 x6 x 7 = 210
15 and 4 and 60 and 2 20 and 3, etc
20 and 30 4 and 15
30 and 60 have an LCM of 60.
You need at least two numbers to find an LCM.
LCM is least common multiple of two or more numbers. LCM of 12 and 15 is 60.
5 and 12
20 and 30
This doesn't work. The LCM of a pair of numbers has to be equal to or larger than the largest number of the pair. If one of the numbers is 60, the other is 120. 60 and 120 have a GCF of 60, not an LCM.
(1, 60) and (2, 60) are two possible pairs.
The LCM of 30 and 60 is 60
30 and 60
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