56 = 2^3*7 so the only odd factors (apart of 1) is 7.
The number 7 is a factor of 7,14,21,28,35,42,49,56,63,70,77,84,91,98,105 or anything multiplied by 7.
One is a perfect square that is a factor of 7.
Prime. It is only divisible by itself and one.
1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 72, 96, 144, 288 2 and 3 are prime.
You want the only shared prime factor to be 7, and the unique prime factors to be 5 and 2. Thus, one answer is 7x2 and 7x5 The number pair is 14 and 35 or 7 and 70.
A prime number,for example: 2, 3, 5, 7, 11, 13, 17, 19 and so on.
Have a pair of dice where one has only sixes and one only fives, for example.Have a pair of dice where one has only sixes and one only fives, for example.Have a pair of dice where one has only sixes and one only fives, for example.Have a pair of dice where one has only sixes and one only fives, for example.
77
-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.
There are only three factors of 49, which are 1, 7, and 49. There are only two prime factors of 49, which are 7 and 7. There is only one distinct prime factor of 49, which is 7. There are not ten factors of 49.
to find the factor pair one has to know the factors of 28 the factors of 28 are 1,2,4,7,14,28 now pair up 1 and 28 is a factor pair because 1x28=28 2 and 14 is a pair because 2x14=28 7 and 4 is a pair because 7x4=28
' 1 ' is their only common factor. They're both prime numbers.
The only factors of 7 are itself and one because it is a prime number
9 and 7 make up a factor pair of 63, not 74.
7 is a prime number; its only factors are one and itself. 1, 7, 11 and 77 are the factors for 77.
2 3 5 7 11 13 17 19 23 29 they are all prime numbers