Using the distributive property of multiplication over addition, x*[x - x] = x*[x + (-x)] = x*x + x*(-x)LHS = x*0 = 0
RHS = x^2 + x*(-x)
Therefore x*(-x) = -x^2 and, by commutativity, -x*x = -x^2
Next
-x*[x - x] = -x*[x + (-x)] = -x*x + -x*(-x)
LHS = -x*0 = 0
RHS = -x^2 + -x*(-x)
Therefore (RHS) -x times -x = +x^2 (LHS).
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there is no net charge on the capacitor because nomber of positive and negative charge and negetive are equal.
The same as the positive ones with negative signs.
Any negative integer can be factored to -1 times its positive value. Because negative one times itself is positive one, when multiplied by each other they cancel out. So if you're multiplying a negative integer A by a negative integer B. Replace A and B with -1*|A| and -1*|B| (You can do this because you know A and B are negative), and use the distributive property to rearrange them. Now you can see the -1*-1 term and equate it to 1, leaving only the |A| and |B| behind. Because two positive numbers multiplied together are always positive, the result will always be positive. Represented algebraically, as long as A and B are negative integers, the following is true: AB = -1|A|*-1|B| = -1*-1|AB| = |AB|.
Positive: Environmental Negative: loss of soverignty