Principle behing the JCB machine is Pascal's Law (Hydralic pressure)
Joseph cyril bamford
In the given scenario, points A, B, C, and D are reflected across a line or point to coincide with points G, J, I, and H, respectively. This reflection implies that each original point and its corresponding reflected point are equidistant from the line of reflection. Therefore, the positions of points A, B, C, and D are symmetrically opposite to points G, J, I, and H concerning the line of reflection. This geometric relationship highlights the properties of reflection in a coordinate plane.
blabber but batter joe ps.. its a name
Star Wars D D D A B-D A B-D J J J K B-D A B-D Godfather 368768676 453 368768676 432 2467 23563
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C. B. J. Snyder died in 1945.
C. B. J. Snyder was born in 1860.
J.-C Nicolet has written: 'From hand to machine'
Z. C. B. J. Hall was created in 1907.
for (i=0; i<IMAX; i++) for (j=0; j<JMAX; j++) c[i,j] = a[i,j] + b[i,j];
J.-B.-C Vial has written: 'Le mari et l'amant'
Matrix-Addition(a,b)1 for i =1 to rows [a]2 for j =1 to columns[a]3 Input a[i,j];4 Input b[i,j];5 C[i, j] = A[i, j] + B[i, j];6 Display C[i,j];
#include<stdio.h> void main() { int a[5],b[5]; int c[10]; int i,j,temp,k; printf("\n enter the elements of array A:=\n"); for(i=0;i<5;i++) scanf("%d",&a[i]); printf("\n enter the elements of array B:=\n"); for(i=0;i<5;i++) scanf("%d",&b[i]); for(i=1;i<5;i++) { for(j=0;j<5-i;j++) { if(a[j]>a[j+1]) { temp=a[j]; a[j]=a[j+1]; a[j+1]=temp; } } for(j=0;j<5-i;j++) { if(b[j]>b[j+1]) { temp=b[j]; b[j]=b[j+1]; b[j+1]=temp; } } } printf("\n the elements of the array A:=\n"); for(i=0;i<5;i++) printf("%d\t",a[i]); printf("\n the elements of the array B:=\n"); for(i=0;i<5;i++) printf("%d\t",b[i]); i=0,j=0,k=0; while(i<5&&j<5) { if(a[i]>b[j]) c[k++]=b[j++]; if(a[i]<b[j]) c[k++]=a[i++]; } if(i<5&&j==5) while(i<5) c[k++]=a[i++]; if(i==5&&j<5) while(j<5) c[k++]=b[j++]; printf("\n the elements of the sorted merged array C:=\n"); for(i=0;i<10;i++) printf("%d\t",c[i]); }
a = 4.0 i - 3.0 j + 1.0 k b = -1.0 i + 1.0 j + 4.0 k → a + b = (4.0 + -1.0) i + (-3.0 + 1.0) j + (1.0 + 4.0) k = 3.0 i - 2.0 j + 5.0 k → a - b = (4.0 - -1.0) i + (-3.0 - 1.0) j + (1.0 - 4.0) k = 5.0 i - 4.0 j - 3.0 k → a - b + c = 0 → c = -(a - b) = -5.0 i + 4.0 j + 3.0 k So that a - b + c = (5.0 - 5.0) i + (-4.0 + 4.0) j + (-3.0 + 3.0) k = 0 i + 0 j + 0 k = 0.
#include<stdio.h> #include<conio.h> void main() { clrscr(); int i,j,m,a[20],b[20],c[20],max; printf("enter no of elements"); scanf("%d",&m); printf("enter elements"); for(i=0;i<=m;i++) { scanf("%d",&a[i]); } max=a[i]; for(i=0;i<=m;i++) { if(max<a[i]) { max=a[i]; } } for(i=0;i<=max;i++) { c[i]=0; } for(j=0;j<=m;j++) { c[a[j]]=c[a[j]]+1; } for(i=0;i<=max;i++) { c[i]=c[i]+c[i-1]; } for(j=m;j>=1;j--) { b[c[a[j]]]=a[j]; c[a[j]]=c[a[j]]-1; } printf("AFTER SORTING"); for(i=0;i<=m;i++) { printf("%d",b[i]); } getch(); }
J. C. B. Richmond has written: 'Egypt, 1798-1952' -- subject(s): History
J. B. C. Munro has written: 'Commercial law' -- subject(s): Commercial law