100 lb of wet air contain 0.10lb water per lb of dry air is mixed with 50 lb another wet air contain 0.02 lb water per lb of dry air calculate the lb of water per lb of dry air in final mixture?

Answer 1

Find the total weight of the water and divide by the total about of air.

((100lb air X .10lb water) + (50lb air x .02lb water)) Divided by (100lb air + 50lb air)=.073lb water per lb of air

Answer 2

First, calculate the total amount of water in the first mixture: 100 lb * 0.10 lb water/lb dry air = 10 lb water. Next, calculate the total amount of water in the second mixture: 50 lb * 0.02 lb water/lb dry air = 1 lb water. Combine the total water from both mixtures (10 lb + 1 lb = 11 lb) and divide by the total dry air (100 lb + 50 lb = 150 lb) to get the final mixture ratio: 11 lb water / 150 lb dry air = 0.073 lb water per lb dry air.