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The equation for the production of methane is C plus 2H2grams yields CH4grams How many liters of hydrogen are needed to produce 20 L of methane?
To produce 1 mole of methane (CH4), you need 2 moles of hydrogen (H2). Since 22.4 L of hydrogen is equivalent to 1 mole at standard temperature and pressure (STP), you would need 44.8 L of hydrogen to produce 1 mole of methane. Therefore, to produce 20 L of methane, you would need 896 L of hydrogen.
How many electrons in a ground-state tellurium atom are in orbitals labeled by l equals 1?
In a ground-state tellurium atom, there are no electrons in orbitals labeled by l equals 1. l equals 1 corresponds to p orbitals, and tellurium's electron configuration fills up to the 5p orbital. So, there are 0 electrons in orbitals with l equals 1 in a ground-state tellurium atom.
How many moles are 22.4 L N2?
Only one mole
Are 0.5 mole of NaOH and 0.5M of NaOH solution same?
No, they are not. "0.5 mole of NaOH" means that you have half a mole of sodium hydroxide. "0.5M of NaOH" means that you have half a mole of sodium hydroxide for every liter of solution. "0.5M" is also commonly written as "0.5 mol/L" or "mol L-1".
What is 140 cm3 equals mL equals equals L?
140 cm3 equals 140 mL (since 1 cm3 is equal to 1 mL). To convert mL to L, you divide by 1000, so 140 mL is equal to 0.14 L.
How many L equals to cc?
1 L = 1,000 cc 1 cc = 0.001 L
Who many ml equals to 1 l?
1000
.1 L equals how many cL -?
10
One kL equals how many L?
1 kL = 1,000 L
How many quarts equals 1 liter?
1 l = 1.05 qt 1 qt = 0.94 l
23 milliliter equals how many L?
1 L = 1 ooo mL and 23 mL = 0.023 L
How many dL are in a L?
1 liter (L) equals 10 deciliter (DL)
How many L equals megaliter?
1,000,000 L = 1 megaL
1000 L equals how many kL?
1 kL
3.6 l equals how many milliliter?
1 L = 1 000 mL and 3,6 L = 3 600 mL
How many kL equals how many L?
Well 1 kL equals to 1,000 LHope this answered your question :)
How many grams of carbon are required to prepare 10 L of CO2 at STP?
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L 10L x 1 mole/22.4 L = 0.446 moles CO2 needed 1 mole C = 1 mole CO2 Therefore you need 0.446 moles C grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
