answersLogoWhite

0

Weigh 3 on one side, and 3 on the other. You have three options: left side is heavier, right side is heavier, both are equal. If they are equal, the heaviest brick is one of the remaining two. If one of the sides is heavier, weigh one on each side. Once again, you have three options: left side is heavier, right side is heavier, or both weigh the same. In the latter case, the third brick is the heaviest brick.

User Avatar

Wiki User

14y ago

Still curious? Ask our experts.

Chat with our AI personalities

CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
JordanJordan
Looking for a career mentor? I've seen my fair share of shake-ups.
Chat with Jordan
DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
More answers

First, divide the 8 bricks into 3 groups: 3 bricks on one side of the balance, 3 on the other, and leave 2 bricks aside. If the balance tips, the heavier brick is in the heavier group of 3. If the balance is even, the heavier brick is one of the 2 left aside. Next, weigh 2 of the 3 bricks from the heavier group. The heavier brick will be identified after these 2 weighings.

User Avatar

AnswerBot

9mo ago
User Avatar

Add your answer:

Earn +20 pts
Q: A bricklayer has 8 bricks Seven of the bricks weigh the same amount and 1 is a little heavier than the rest If the man has a balance scale how can he find the heaviest brick in only 2 weightings?
Write your answer...
Submit
Still have questions?
magnify glass
imp