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∙ 11y ago33.35 grams
I used the density=mass/volume formula. To get the volume of a cube you do the following:
1.2 *1.2 * 1.2=1.728
Now you plug your values in the formula:
density=mass/volume
mass=density*volume
mass=19.3 * 1.2 = 23.16
mass=33.35 grams
Wiki User
∙ 12y agoDensity is calculated by dividing the mass of an object by its volume. To find the volume of a cube, you cube the length of one of its sides. In this case, the volume is (1.42 cm)^3 = 2.43 cm^3. Therefore, the density of the metal cube is 16.3 g / 2.43 cm^3 = 6.70 g/cm^3.
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∙ 11y agoDensity = mass/volume = 16.3/(1.42)3 = 5.693 gram/cm3(rounded)
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∙ 13y agoThe solid's density is about 6,091.846 kg/m3 or 6.092 g/cm3
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∙ 12y agodensity = mass/volume
volume of cube = 4.01 x 4.01 x 4. 01 = 64.48 cu cm
density = 1.35/64.48 = 0.021 g/cc
Molecular Weight: 26.98The density of industrial qualities of aluminum lies around 2.7A cube 10cm each edge weighs 2700 grams
To find the length of one edge of the cube, you would calculate the cube root of the volume. In this case, the cube root of 150 cubic centimeters is approximately 5.3 centimeters. Therefore, the length of one edge of the cube is 5.3 centimeters.
A cubic yard is a cube that measures one (linear) yard on each edge. There are 36 inches to the (linear) yard. To calculate the volume of a cube, raise the length of its edge to the power of three. (In other words, V = L cubed.) The answer is: 46656
You would need 8 smaller cubes with 2 cm edge to form a larger cube with a 4 cm edge.
Think of it as the difference in moment of inertias for two solid cubes. Calculate the moment of inertia of a solid cube with dimensions equal to the inner dimensions of your hollow cube. Then calculate the moment of inertia of a solid cube with dimensions equal to the outer dimensions of your hollow cube. Subtract the moment of inertia of the inner dimensions from the moment of inertia of the outer dimensions to get the moment of inertia of what's left. Same concept applies to finding the area of a thin-walled circle. Outer area - inner area = total area. Outer moment of inertia - inner moment of inertia = total moment of inertia. This approach won't work however if you're considering hollow shell - a cube with walls of zero thickness. If the axis of rotation goes through the cube center, perpendicular to one of its walls, first calculate moment of inertia of the wall that the axis passes through (let's call it Ia). For all equations below d equals surface density(mass per unit of area) and a is length of cube's side. Ia= d * a4 / 6 Then you have to calculate moments of inertia of four walls parallel to the axis. This will be Ib=4 * Iwall=4*d*a4/3. Total moment of the shell will be then: I=2*Ia+Ib=1.5*d*a4. If the axis is through the center and ┴ one face, I = (m/6)*[a² - (a-t)²], or I = (m/6)(2at - t²) for any value of t, however small. Source: CRC Std Math Tables
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The density is (32)/(the length of each edge of the cube)3
Molecular Weight: 26.98The density of industrial qualities of aluminum lies around 2.7A cube 10cm each edge weighs 2700 grams
To find the length of one edge of the cube, you would calculate the cube root of the volume. In this case, the cube root of 150 cubic centimeters is approximately 5.3 centimeters. Therefore, the length of one edge of the cube is 5.3 centimeters.
27 cubic centimeters
6*s2 where s is the length of an edge.
it is 2744 cubic centimetres
1357.2
The volume of a cube is found by cubing the length of an edge. To find the measure of an edge of a cube of a known volume, simply find the cube root of the volume. In this case, the cube root of 1728 is 12. It's actually plus or minus 12, but we drop the minus 12 because shapes can have negative dimensions. Given a cube of known volume, the length of an edge can be found by finding the cube root of the cube's volume.
The atomic radius of nickel is 124 pm. To calculate the density of the metal, we first need to determine the volume of the unit cell, which can be calculated using the formula: volume = (edge length)^3. Then, the density can be calculated by dividing the atomic mass of nickel by the volume of the unit cell.
173 - 23 =165cm3
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