28,2 [psi ] = 28,2 [pounds / square inch ] = 28,2 [ lbf /in^2] Definition 1 inch = 25,4 * 10^-3 m (metre)
28,2 [pounds / in^2] / 25,4^2 * 10^-6 [ in ^2 / m^2] =
0,04371 * 10 ^6 [pounds /m^2] Definition: 1 pound = 0,453 592 37 kg 28,2 psi = 0,04371 * 10^6 [pounds /m^2] *0,453 592 37 [kg / pound] 28,2 psi = 0,0198 * 10^6 [kg / m^2] 1 kgf = 1kg * g [m/s^2] = 1[kg]* 9,81 [m*s^-2] = 9,81N 28,2 psi = 0,0198 * 10^6 [kg / m^2] * 9,81 [N / kgf] =
0,194*10^6 [N / m²] = 194.000 Pa
Definition: 1 Pa = 1 N / m² 1kPa = 1000 Pa 28,2 psi = 194 kPa shorter 1 psi = 6,89476 kPa
28,2 psi = 28,2 [psi] * 6,89476 [kPa/psi] = 194,43 kPa Roger.
The gauge pressure is the difference between the absolute pressure and atmospheric pressure. If atmospheric pressure is approximately 101.3 kPa, then the gauge pressure would be 448.980 kPa (550.280 kPa - 101.3 kPa).
Total pressure = ppO2 + ppH2 + ppN2ppN2 = Total pressure - (ppO2 + ppH2)ppN2 = 282 kPa - (110+106 kPa) = 282kPa - 216kPappN2 = 66 kPa = partial pressure of nitrogen
The absolute pressure can be calculated by adding the atmospheric pressure to the gauge pressure. If the atmospheric pressure is 101.3 kPa, then the absolute pressure of the gas would be 206 kPa + 101.3 kPa = 307.3 kPa.
The absolute pressure in the apparatus can be calculated by converting the barometer reading to kPa, which is 97.3 kPa. The equivalent pressure in the apparatus is then 97.3 kPa - 10 kPa = 87.3 kPa.
To convert kilopascals (kPa) to bar gauge (barg), subtract the atmospheric pressure (typically around 101.3 kPa) from the given pressure. In this case, 345 kPa - 101.3 kPa = 243.7 kPa absolute. Then, convert the absolute pressure to barg by dividing by 100, as 1 bar = 100 kPa. Therefore, 243.7 kPa / 100 = 2.437 barg.
16.2 bar = 1,620 kPa
The gauge pressure is the difference between the absolute pressure and atmospheric pressure. If atmospheric pressure is approximately 101.3 kPa, then the gauge pressure would be 448.980 kPa (550.280 kPa - 101.3 kPa).
Total pressure = ppO2 + ppH2 + ppN2ppN2 = Total pressure - (ppO2 + ppH2)ppN2 = 282 kPa - (110+106 kPa) = 282kPa - 216kPappN2 = 66 kPa = partial pressure of nitrogen
The gauge pressure is the absolute pressure minus atmospheric pressure. If atmospheric pressure is considered to be 101 kPa, then the gauge pressure would be 219 kPa.
Total pressure = ppO2 + ppH2 + ppN2ppN2 = Total pressure - (ppO2 + ppH2)ppN2 = 282 kPa - (110+106 kPa) = 282kPa - 216kPappN2 = 66 kPa = partial pressure of nitrogen
If a gas has a gage pressure of 156 kPa its absolute pressure is approximately?
if the gauge pressure is 206 kPa, absolute pressure is 307 kPa
The absolute pressure can be calculated by adding the atmospheric pressure to the gauge pressure. If the atmospheric pressure is 101.3 kPa, then the absolute pressure of the gas would be 206 kPa + 101.3 kPa = 307.3 kPa.
To convert between absolute pressure in kPa to gauge pressure in mm Hg, you can use the conversion factor of 1 kPa = 7.5 mm Hg. Therefore, if the required absolute pressure is 20 kPa, the corresponding gauge pressure would be 20 kPa * 7.5 mm Hg/kPa = 150 mm Hg.
The absolute pressure in the apparatus can be calculated by converting the barometer reading to kPa, which is 97.3 kPa. The equivalent pressure in the apparatus is then 97.3 kPa - 10 kPa = 87.3 kPa.
The gauge pressure would be 448.955kPa.
To convert pressure from kPa to lbs/in^2, divide by 6.895. So, 424 kPa is equal to 61.5 lbs/in^2.