Sammcw
Divide 158 by 156. The answer is the density in grams per ml. In this case, very close to 1 g/ml Density = MASS divided by VOLUME
Wiki User
∙ 16y agoThe density of the seawater sample is calculated by dividing the mass (158 grams) by the volume (156 ml). Therefore, the density of the seawater sample is approximately 1.01 grams per milliliter.
About 3/5 cup
156 ml = 5.27 US fluid ounces.
First, calculate the total mass of the solution: 0.400 L * 1.28 g/mL = 0.512 g. Since the solution is 39.1% sulfuric acid by mass, multiply the total mass by 0.391 to find the mass of sulfuric acid: 0.512 g * 0.391 = 0.200 g. Therefore, there are 0.200 grams of sulfuric acid in 0.400 L of the battery acid solution.