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A student determined that the density of a sample of tin is 8 00 mL when the actual density of tin is 7 28 mL What was the percent error in the student's calculation?
Wiki User
∙ 14y ago
((8 - 7.28)/7.28) x 100 = 9.89%
Wiki User
∙ 14y ago
The student's calculation resulted in a density that is higher than the actual density. To calculate the percent error, the formula (|measured value - actual value| / actual value) x 100 is used. Plugging in the values, the percent error would be [(8.00 - 7.28) / 7.28] x 100 = 9.89%.
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