Xokisskayxo
well before sig digs you get 336.46, but since you asked for 3 significant digits, then it becomes 336
Wiki User
∙ 15y agoThe sum of 12.16 and 324.3 is 336.5 when rounded to three significant figures.
Roughly 1216 kilometers.
Essentially yes. Plants do have cancer-like diseases This forum has the same question and a far better answer than any I could provide. http://www.askabiologist.org.uk/punbb/viewtopic.php?id=1216
The weight of an object that is 100 pounds on Earth would be approximately 38 pounds on Mercury. This is because Mercury's gravity is about 38% that of Earth's, so the object would weigh less on Mercury.
To calculate the number of kilograms of Al2(SO4)3 needed to provide 1.00 x 10^30 atoms of oxygen, you first need to find the molar mass of Al2(SO4)3. Molar mass of Al2(SO4)3 = 2*(26.98) + 3*(32.07) + 12*(16) = 226.98 + 332.07 + 1216 = 226.98 + 3*32.07 + 192 = 53.96 + 96.21 + 192 = 342.17 g/mol. Number of molecules in 1kg of Al2(SO4)3 = 1000 / 342.17 = 2.92 mol. Number of atoms of Oxygen in 1kg of Al2(SO4)3 = 2.92 * 6.022 * 10^23 = 1.76 x 10^24 atoms of oxygen. Therefore, to provide 1.00 x 10^30 atoms of oxygen you would need approximately 5.68 x 10^5 kg of Al2(SO4)3.
CFCs, and are known ozone depleters. See the link below for what their effects are.: * Refrigerant R-10 is CCl4. * Refrigerant R-11 is CCl3F. * Refrigerant R-12 is CCl2F2. * Refrigerant R-13 is CClF3. HCFCs, and are known ozone depleters but with lowered suvivability to reach the ozone layer. See the link below for what its effects are. * Refrigerant R-22 is HCClF2. * Refrigerant R-40 is CH3Cl. It is responsible for ~17% of chlorine-assisted ozone destruction in the statosphere. It is today primarily produced by plants, and the combustion of organic waste materials, since its use in industry was stopped some time ago. CFCs inclusive of HCFCs, are ~82% of the chlorine currently found in the stratosphere Some refrigerants that do not contain chlorine or bromine are: R-14, R-23, R-32, R-41, R-50, R-116, R-125, R-E125, R-134, R-134a, R-E134, R-143, R-143a, R-143m, R-E143a, R-152, R-152a, R-161, R-170, R-218, R-227ca, R-227ca2, R-227ea, R-227me, R-236cb, R-236ea, R-236fa, R-236me, R-FE-36, R-245ca, R-245cb, R-245ea, R-245eb, R-245fa, R-245mc, R-245mf, R-245qc, R-254cb, R-254pc, R-263, R-272, R-281, R-290, R-C318, R-3-1-10, R-347mcc, R-347mmy, R-365mfc, a few of the blends between R-400 and R-600, R-600, R-600a, R-601, R-601a, R-610, R-611, R-630, R-631, R-702, R-704, R-717, R-718, R-720, R-728, R-732, R-740, R-744, R-744A, R-764, R-784, R-1114, R-1132, R-1141, R-1150, R-1216, R-1270 This list includes chemicals that are so stable that they also can accumulate over decades as CFCs did, and yet new problems may result from their use and/or release into the environment. Others of them are fuels (so are flammable), components of natural gas, and may not accumulate, but can contribute to ozone pollution as a VOC.
1810 = 1216
1216+400=1616
973 (US Hardback), 976 (UK Hardback), 1216 (US Paperback)
8.1067
The LCM of 9 and 1216 is 10944 The LCM of 9, 12 and 16 is 144.
You need at least two numbers to find a GCF. If that's 12 and 16, the GCF is 4.
0.25 x 1216 Or if you want to use number sense then you could take a fourth of it. 1216 divided by 4=304
The factors of 1216 are 1, 2, 4, 8, 16, 19, 32, 38, 64, 76, 152, 304, 608, and 1216.
1216/1000 = 152/125 = 127/125
There are 1.609344 kilometres in one mile. Therefore, rounded to two decimal places, 1216 kilometres is equal to 1216/1.609344 = 755.59 miles.
One kilometre is equal to 1000 x 100 = 100000 centimetres. Therefore, 1216 kilometres is equal to 1216 x 100000 = 121600000 centimetres.
Innocent III was pope between the years 1198 and 1216.