An electric lamp is marked 100w and 220v it is used for 5 hours daily calculate its resistance while glowing and energy consumed in kw per day?

Answer 1

power = voltage x current; current = power / voltage = 25W / 220V = 0.11...A

resistance = voltage / current = 220V / 0.11A = 1936 ohms

power = energy / time; energy = power x time = 25W x 1 day = 0.025kW x 1 day = 0.025 kW-days or 0.6 kW h

note: energy is not measured in kw per day, usually kW-hours (kW h).

Answer 2

If the lamp consumes energy at the rate of 100w when energized by 220v, then its resistance is

E2/P = (220)2/100 = 484 ohms.

"Kw" is not a unit of energy. Some units of energy are:

-- kilowatt-hour

-- watt-hour

-- watt-second (joule)

-- newton-meter (joule)

-- foot-pound

(100 watts) x (5 hours per day) = 500 watt-hours per day = 1/2 Kilowatt-hour per day.

(500 watt-hour/day) x (3,600 sec/hour) = 1,800,000 joules (1.8 megajoules) per day

Answer 3

To calculate the resistance, you might first calculate the current: 25 W / 220 V = 0.114 A. Resistance: R = V / I = 1930 Ohms.

Energy is 25 W = 25 watt-second per second. Multiply that by 86400 (seconds per day), and you get 2160000 ws/day. Divide that by 3.6 million, to get 0.6 kWh per day.

Answer 4

To calculate the resistance of the lamp, we can use Ohm's Law: R = V^2 / P, where V is the voltage (220V) and P is the power (100W). Substituting these values, we get R = 220^2 / 100 = 484 ohms. To calculate the energy consumed per day, we first convert the power to kW: 100W = 0.1 kW. Then, energy consumed per day = power x time = 0.1 kW x 5 hours = 0.5 kWh.