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An electron requires 3.8 x 10-19 J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?
Wiki User
∙ 14y ago
5.10 x 10^14 hz
Wiki User
∙ 11y ago
Wiki User
∙ 11y ago588 nm
The energy of a photon is given by E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. Rearranging the formula to solve for λ gives λ = hc / E. Plugging in the values gives λ = (6.626 x 10^-34 J·s) * (3.00 x 10^8 m/s) / 3.8 x 10^-19 J = 523 nm. The wavelength of the photon is 523 nm.
Wiki User
∙ 14y agoLong way. Energy = Planck's constant * speed of light/lambda in meters
3.8 X 10^-19 J = (6.626 X 10^-34 J*s)(2.998 X 10^8 m/s)/ Lambda in meters
= 5.2 X 10^-7 meters, which is ~ 523 nanometers in wavelength.
Wiki User
∙ 14y agoEnergy = Planck's constant * speed of light/Lambda(wavelength)
4 X 10^-17 J = (6.626 X 10^-34J*s)(2.998 X 10^8m/s)/Lambda
= 4.97 X 10^-9 meters or, 4.97 nanometers ( short wavelength )
Wiki User
∙ 14y agoE=hC/λ rearranges to λ=hC/E
λ= (6.63 x 10-34) x (3 x 108) / 3.8 x 10-19
λ= 5.23 x 10-7m
Wiki User
∙ 8y agoThe wavelength is 609,34 nm.
Wiki User
∙ 14y ago522 nm
Wiki User
∙ 12y ago588 nm
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An electron requires 4.4 x 10 to the negative 19th power J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?
440 - 460 nm
Suppose an electron is accelerated from rest through a potential difference of 150kV. What wavelength shoud it have?
The wavelength of the electron can be calculated using the de Broglie wavelength formula, which is λ = h/p, where λ is the wavelength, h is the Planck constant, and p is the momentum of the electron. The momentum of the electron can be calculated using the relation p = sqrt(2mE), where m is the mass of the electron and E is the energy gained by the electron from the potential difference. By substituting the given values into these equations, you can calculate the wavelength of the electron.
Which color of light does the smallest energy drop of an electron produce?
The smallest energy drop of an electron produces red light. When an electron transitions to its lowest energy level, it emits a photon with the least energy, corresponding to the red wavelength of light.
What happens to an electron during an electron transition?
Drops to a lower energy level and emits one photon of light.
At Which wavelength will electrons travel fastest when hitting uranium?
Electrons will travel fastest when hitting uranium at a specific wavelength corresponding to their maximum kinetic energy, which is determined by the energy of the incoming electrons and the properties of uranium. This wavelength can be calculated using the de Broglie wavelength formula involving the electron's energy and momentum.
An electron requires 4.4 x 10-19 J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?
450 nm
An electron requires 4 x 10-17 J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?
4.8 - 5.2 nm
An electron requires 4.4 x 10 to the negative 19th power J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?
440 - 460 nm
That An electron requires 4 times 10-17 j of energy to be removed from it's atom what is the wavelength of a photon that has this much energy?
The wavelength is w = hc/E = .2E-24/4E-17 = 5E-9 meters.
When an electron in atom changes energy states a photon is emitted If the photon has a wavelength of 550 nm how did the energy of the electron change?
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
Why is a shorter wavelength of light emitted when an electron falls from n4 to n1 than when an electron falls from n2 to n1?
When an electron falls from n4 to n1, it releases more energy because it is transitioning between high energy states. This higher energy transition corresponds to a shorter wavelength of light being emitted, according to the energy of the photon being inversely proportional to its wavelength. In contrast, when an electron falls from n2 to n1, the energy released is less, resulting in a longer wavelength of light emitted.
Why does Be have a much larger second ionization energy than the first?
Beryllium has a much larger second ionization energy than the first because after losing its first electron, the remaining electron is held more tightly due to increased electrostatic attraction from the positively charged nucleus. This results in a higher energy requirement to remove the second electron.
What can be removed from an atom if ionization energy is supplied?
An electron can be removed from an atom if ionization energy is supplied. Ionization energy is the energy required to remove an electron from an atom, resulting in the formation of a positively charged ion.
Why the addition of two electrons or removal of one electron requires more energy in oxygen atom?
Adding electrons to an oxygen atom requires more energy because its electron shells are already filled and adding more electrons would create repulsion due to increased electron-electron interactions. Removing an electron requires more energy because oxygen has a strong attraction to electrons due to its high electronegativity, making it difficult to remove an electron.
What is removed when ionization energy is applied?
an electron
If enough energy was added to remove an electron for calcium which energy level would the electron be removed?
The electron would be removed from the outermost energy level, which is the fourth energy level, for calcium.
Suppose an electron is accelerated from rest through a potential difference of 150kV. What wavelength shoud it have?
The wavelength of the electron can be calculated using the de Broglie wavelength formula, which is λ = h/p, where λ is the wavelength, h is the Planck constant, and p is the momentum of the electron. The momentum of the electron can be calculated using the relation p = sqrt(2mE), where m is the mass of the electron and E is the energy gained by the electron from the potential difference. By substituting the given values into these equations, you can calculate the wavelength of the electron.
