5.10 x 10^14 hz
440 - 460 nm
The wavelength of the electron can be calculated using the de Broglie wavelength formula, which is λ = h/p, where λ is the wavelength, h is the Planck constant, and p is the momentum of the electron. The momentum of the electron can be calculated using the relation p = sqrt(2mE), where m is the mass of the electron and E is the energy gained by the electron from the potential difference. By substituting the given values into these equations, you can calculate the wavelength of the electron.
The smallest energy drop of an electron produces red light. When an electron transitions to its lowest energy level, it emits a photon with the least energy, corresponding to the red wavelength of light.
Drops to a lower energy level and emits one photon of light.
Electrons will travel fastest when hitting uranium at a specific wavelength corresponding to their maximum kinetic energy, which is determined by the energy of the incoming electrons and the properties of uranium. This wavelength can be calculated using the de Broglie wavelength formula involving the electron's energy and momentum.
450 nm
4.8 - 5.2 nm
440 - 460 nm
The wavelength is w = hc/E = .2E-24/4E-17 = 5E-9 meters.
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
The electron would be removed from the outermost energy level, which is the fourth energy level, for calcium.
When an electron falls from n4 to n1, it releases more energy because it is transitioning between high energy states. This higher energy transition corresponds to a shorter wavelength of light being emitted, according to the energy of the photon being inversely proportional to its wavelength. In contrast, when an electron falls from n2 to n1, the energy released is less, resulting in a longer wavelength of light emitted.
An electron can be removed from an atom if ionization energy is supplied. Ionization energy is the energy required to remove an electron from an atom, resulting in the formation of a positively charged ion.
an electron
The energy to remove 1 electron is the first ionization energy. To remove a second electron requires more energy. This is because the electron being removed now has to overcome the +1 positive charge introduced after the 1st electron was removed.
Type your answer here... when adding an electrons to oxygen it needs more energy in electron affinity in order to attract electrons from other atoms to be stable.and we know that oxygen is in short of two electrons.so in the other hand when an electron is removed from oxygen it will be unstable and will be needing more ionization energy to be able to remove an electron to it.Thus mean indeed when adding or removing electrons for oxygen it requires energy.
The energy of a photon with a wavelength of 500 nm is approximately 2.48 keV.