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∙ 12y ago2L/293K=1L/x therefore x=293/2 and x approximately = 146.5K
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∙ 12y agoThe temperature change when a gas is compressed without any heat exchange can be calculated using the ideal gas law. First, calculate the initial pressure of the gas using P1V1 = P2V2. Next, use the combined gas law to calculate the final temperature using the initial pressure, volume, final volume, and initial temperature. Subsequently, calculate the temperature decrease by subtracting the final temperature from the initial temperature.
To calculate an increase, you can use the formula: increase = (new value - original value). To calculate a decrease, you can use the formula: decrease = (original value - new value). The percentage increase or decrease can be found by dividing the increase or decrease by the original value and multiplying by 100.
To calculate corrected temperature, you typically need to apply a correction factor to the measured temperature. This correction factor is often determined by referencing a calibration table or using a mathematical formula provided by the manufacturer or a relevant standard organization. Make sure to accurately follow the instructions provided to ensure the corrected temperature is calculated correctly.
Lowering the temperature to 100°C would decrease the rate of the forward reaction in the Haber process. This is because lower temperatures slow down the kinetic energy of the particles, resulting in fewer collisions between molecules, which in turn reduces the rate of reaction.
The density of water decreases as it is heated from 30 to 100 degrees Celsius. This is because the water molecules gain kinetic energy and move further apart, resulting in a decrease in density.
100 degress
20%% decrease = |original value - new value|/original value * 100%= |75 - 60|/75 * 100%= 15/75 * 100%= 0.20 * 100%= 20%
first calculate the value of increase e.g. if 100 increases to 110 then the increase is 10. Then you calculate the percentage increase by diving the increase by the original number then multiply by 100 i.e. (10 divided 100 = 0.1, multiplied by 100 = 10%) or (10/100)*100 same for % decrease but in reverse.
A - A x 1 / 100 = Xwhere 'A' is the number and 'X' is the result of decreasing by 1% from A.Example: To decrease 1% from 20 you would calculate as20 - 20 x 1 / 100 = 19.8
To calculate an increase, you can use the formula: increase = (new value - original value). To calculate a decrease, you can use the formula: decrease = (original value - new value). The percentage increase or decrease can be found by dividing the increase or decrease by the original value and multiplying by 100.
The density of water increase from 100 oC to 4 oC (here is a maximum); after this temperature the density decrease.
pure water (with no impurities added ) can only boil at 100 degrees Celsius , no other temperature . But if we add impurities to it than the temperature at which the water will boil can increase or decrease. Another point is that when we increase or decrease the atmospheric pressure, the temperature at which ordinary water boils (i.e.100 degrees Celsius) can also increase or decrease.
Decrease = Before - After = 9.82 - 9.71Relative decrease = Decrease/Before = (9.82 - 9.71)/9.82Percentage decrease = 100*Relative decrease = 100*(9.82 - 9.71)/9.82= 1.12% approx.Decrease = Before - After = 9.82 - 9.71Relative decrease = Decrease/Before = (9.82 - 9.71)/9.82Percentage decrease = 100*Relative decrease = 100*(9.82 - 9.71)/9.82= 1.12% approx.Decrease = Before - After = 9.82 - 9.71Relative decrease = Decrease/Before = (9.82 - 9.71)/9.82Percentage decrease = 100*Relative decrease = 100*(9.82 - 9.71)/9.82= 1.12% approx.Decrease = Before - After = 9.82 - 9.71Relative decrease = Decrease/Before = (9.82 - 9.71)/9.82Percentage decrease = 100*Relative decrease = 100*(9.82 - 9.71)/9.82= 1.12% approx.
100 to 18 is an 82% decrease.
the new value minus the old value, then divide it by the old value, times 100%, if the value is positive, it's the percentage increase, if it's negative, it's the percentage decrease.
The decrease in temperature with an increase in elevation is known as the lapse rate. As you move higher above sea level, the air pressure decreases, causing the air to expand and cool down. This cooling effect is why the temperature drops by an average of 0.6 degrees Celsius per 100 meters of elevation gain.
It is a 37% decrease
100% decrease.