briefly discuss the errors tahat occur in the above titration and the change in the colour of the indicators.
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To calculate the molarity of a solution, you first need to find the number of moles of the solute. In this case, the molar mass of CuSO4 · 5H2O is 249.68 g/mol. So, 75 g is equal to 0.3 moles (75g / 249.68 g/mol). Next, divide the moles of the solute by the volume of the solution in liters to get the molarity. In this case, the molarity is 0.3 moles / 1.0 L = 0.3 M.
10kg of water contains 10l of water. So morality is 0.2mildm-3.
There are approximately 0.169 cups in 40 mL.
The reaction between methane and oxygen to form carbon dioxide and water is balanced as follows: CH4 + 2O2 -> CO2 + 2H2O. Using the ideal gas law, we can calculate the final volume by determining the number of moles of methane and oxygen reacting and then finding the volume of the products formed at the same conditions of temperature and pressure.
Using the ideal gas law (PV = nRT), we can calculate the number of moles of gas present in the container. First, convert the temperature to Kelvin (35°C + 273 = 308K). Then plug in the values: 3.84 atm * 10 L = n * 0.0821 Latm/molK * 308 K to solve for n. This gives approximately 1.5 moles of gas in the container.
5240 ml is equivalent to 5.24 liters. To find the fraction, divide 5.24 liters by the total amount of 10 liters. Therefore, the fraction of 10 liters that 5240 ml represents is 5.24/10 or 0.524.