First, let me clarify the question:
You want to use a 16V, 4.5 amp power supply to operate a device that uses 16V, 1.5 amps.
That's not a problem, the larger power supply simply has the capacity of 4.5 amps, meaning that you can use anything UP TO 4.5 amps.
On the other hand...
if you want to try using a device that pulls 4.5 amps, using a 1.5 amp power supply... sorry, won't work out well. That would overheat the power supply and it would fail.
Multiplying 400 volts by 45 amps would give you a power output of 18000 watts, which is equivalent to 18 kilowatts (kW).
To calculate the amperage per phase, you can use the formula: Current (A) = Power (W) / (Square Root(3) x Voltage (V)). In this case, for a 45 kW unit at 380 volts, the amperage per phase would be approximately 70 amps.
I am assuming that you are talking single phase. 45 kva is k = 1000, v = volts, a = amps. 45 kva is 45000 volt / amps. Input 45000 divided by 208 volts = 216 amps. Output 45000 divided by 120 volts = 375 amps. There are other losses in the transformer but as a general rule of thumb this is the calculation that you would use.
To determine the running amps of a 45 kW motor, you would need to know the voltage at which it operates. You can use the formula: Amps = (kW x 1000) / (Volts x power factor). Once you have the voltage and power factor information, you can plug them into the formula to calculate the running amps.
A #8 copper conductor with an insulation factor of 60 degrees C is rated at 40 amps, insulation factor of 75 or 90 degrees C is rated at 45 amps.If the breakers rating is 90 degrees C then the amperage can be boosted for 60 degree wire to 40 amps, 75 degree C wire to 50 amps and 90 degree C wire to55 amps.
The current is 1.4 amps, as already stated. The voltage is 45 x 1.4 volts.
Each phase supplies 15 kVA. The primary has a line-to-neutral voltage of 277 v so the line current is 15,000 / 277 or 54 amps. The secondary has a line-to-neutral voltage of 120v so the current is 15,000/120 or 125 amps.
Multiplying 400 volts by 45 amps would give you a power output of 18000 watts, which is equivalent to 18 kilowatts (kW).
To calculate the required amperage for a 45 kW shredder operating at 415 volts in a three-phase system, you can use the formula: Amps = Power (Watts) / (Voltage × √3). For a 45 kW (or 45,000 watts) shredder, this would be: Amps = 45,000 / (415 × √3), which equals approximately 62.5 amps. Therefore, you would need around 62.5 amps for the shredder.
To calculate the amperage per phase, you can use the formula: Current (A) = Power (W) / (Square Root(3) x Voltage (V)). In this case, for a 45 kW unit at 380 volts, the amperage per phase would be approximately 70 amps.
Just add the amps (3.2 amps).
The answer to the LCM of 45 and 15 is 45.
A walmart ever last wiil be fine at 350 c-amps, if you use your mower at temps below 45-f, or have more than 20 hp then go up to 420 c-amps.
3 * 15 = 45 or 15 = 45 / 3 or 3 = 45 / 15
I am assuming that you are talking single phase. 45 kva is k = 1000, v = volts, a = amps. 45 kva is 45000 volt / amps. Input 45000 divided by 208 volts = 216 amps. Output 45000 divided by 120 volts = 375 amps. There are other losses in the transformer but as a general rule of thumb this is the calculation that you would use.
To determine the running amps of a 45 kW motor, you would need to know the voltage at which it operates. You can use the formula: Amps = (kW x 1000) / (Volts x power factor). Once you have the voltage and power factor information, you can plug them into the formula to calculate the running amps.
45 - 15 = 3030 - 15 = 15