0
Determine the number of formula units that are in 0.688 moles of AgNO3?
Wiki User
∙ 13y ago
0.688 moles*6.02x1023
=4.14x1023 Formula units
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How many moles of silver of ions are presented in 32.46 g of AgNO3?
The number of moles is 0,19.
How do you determine the empirical formula of a metal oxide?
To determine the empirical formula of a metal oxide, first determine the moles of metal and oxygen in a given sample. Then, divide the moles of each element by the smallest number of moles to get a whole number ratio. This ratio represents the empirical formula of the metal oxide.
How many moles are in 680g of AgNO3?
Roughly 4 moles.
How many silver atoms would be in 4.55 moles of AgNO3?
To find the number of silver atoms in 4.55 moles of AgNO3, first calculate the molar mass of AgNO3 which is 169.87 g/mol. Then set up a ratio using Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. The calculation would be 4.55 moles x (6.022 x 10^23 atoms/mol) = 2.74 x 10^24 silver atoms in 4.55 moles of AgNO3.
Do chemical reactions contain the same number of moles as reaction proceeds?
Not necessarily. Some reactions do have the same number of moles, and some do not.Examples: NaCl + AgNO3 ==> NaNO3 + AgCl same # of moles N2 + 3H2 ==> 2NH3 different # of moles
How many formula units of AgNO3 are present in 147g of this compound?
To determine the number of formula units of AgNO3 in 147g of the compound, you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Next, divide the given mass (147g) by the molar mass to find the number of moles present in the sample. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
How many moles are in 4.5 g of AgNO3?
To find the number of moles in 4.5 g of AgNO3, you first need to determine the molar mass of AgNO3 which is 169.87 g/mol. Then you can use the formula: moles = mass / molar mass. Therefore, moles = 4.5 g / 169.87 g/mol ≈ 0.0265 moles.
How many moles of agno3 are needed to prepare 0.50 l of a 4.0 m solution?
To calculate the moles of AgNO3 needed to prepare a 4.0M solution in 0.50L, you can use the formula: moles = Molarity x Volume (in liters) Substitute the values into the formula: moles = 4.0 mol/L x 0.50 L = 2.0 moles of AgNO3.
How many moles of silver nitrate do 2.8881015 formula untied equal?
To find the number of moles in 2.8881015 formula units of silver nitrate, you first need to know the molar mass of silver nitrate (AgNO3), which is 169.87 g/mol. Then, you can use the formula: moles = formula units / Avogadro's number. Therefore, moles = 2.8881015 / 6.022 x 10^23 = 4.79 x 10^-24 moles.
How many moles in 4.50 grams of silver nitrate?
To find the number of moles in 4.50 grams of silver nitrate (AgNO3), you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Then, use the formula: moles = mass/molar mass. So, 4.50 grams of AgNO3 is equal to 0.0265 moles.
How many moles of AgNO3 does 85 grams of AgNO3 represents?
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
What is the molarity of a solution if 255 grams AgNO3 is dissolved in 1500 mL of solution?
First, calculate the number of moles of AgNO3 using its molar mass. Then, convert the volume of the solution from mL to liters. Finally, divide the number of moles of AgNO3 by the volume in liters to find the molarity.
What mass of solid agcl is obtained when 25 ml of 0.068m agno3 reacts with excess of aqueous hcl?
To find the mass of AgCl formed, first calculate the number of moles of AgNO3 using the formula moles = Molarity x Volume (in liters). Then, use the balanced chemical equation to determine the mole ratio between AgNO3 and AgCl. Finally, convert the moles of AgCl to grams using the molar mass of AgCl (107.87 g/mol).
How many moles of silver of ions are presented in 32.46 g of AgNO3?
The number of moles is 0,19.
How many moles of silver are present in 32.46g of AgNO3?
To find the number of moles of silver in 32.46g of AgNO3, first calculate the molar mass of AgNO3 (169.87 g/mol). Then, divide the given mass by the molar mass to find the number of moles (32.46g / 169.87 g/mol ≈ 0.191 moles). Since there is one mole of Ag in one mole of AgNO3, there are 0.191 moles of silver present.
How many mL of .117M AgNO3 solution would be required to react exactly with 3.82 moles of NaCl?
To find the volume of AgNO3 solution needed, we first calculate the moles of NaCl using the molar ratio between AgNO3 and NaCl in the balanced chemical equation. Then, we use the molarity of the AgNO3 solution to determine the volume: moles of NaCl x (1 mol AgNO3 / 1 mol NaCl) x (1 L / 0.117 mol) x 1000 mL = volume in mL.
How many moles of CaCl2 are in 2.00 1024 formula units?
To find the number of moles of CaCl2 in 2.00x10^24 formula units, you need to first determine the molar mass of CaCl2, which is 110.98 g/mol. Then, divide the number of formula units by Avogadro's number (6.022x10^23) to convert to moles. This gives you approximately 3.32 moles of CaCl2.
