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Determine the pH of a 0.461 m c6h5co2h m solution if the ka of c6h5co2h is 6.5 x 10-5?
For this type of problem we use an I.C.E. diagram
C6H5CO2H
C6H5CO2
H3O
0.461 M
?
?
-X
+X
+X
0.461 - X
+X
+X
Ka of C6H5CO2H is 6.5 x 10-5.
Ka = [C6H5CO2][H3O]/[C6H5CO2H]
6.5 x 10-5 = x2/(0.461 - x)
after manipulation
X2+ (6.5 x 10-5)x - (2.99 x 10-5)
--> Plug in the Quadratic Formula
X = +/- 0.0055
[H3O] = 0.0055
-Log(0.0055) = pH
pH = 2.26
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