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What is the chemical equation for magnesium plus chlorine?
Magnesium has a charge of +2 and Chloride has a charge of -1. In order to make magnesium chloride have a net charge of zero, there must be twice as much of the chloride ion than the magnesium ion. The ratio of magnesium to chloride is therefore 1:2. With this knowledge, we can write the chemical equation MgCl2.
How do you balance BrCl --- Cl2 plus Br2?
To balance the chemical equation BrCl → Cl2 + Br2, you need to make sure that there are the same number of atoms of each element on both sides of the equation. Start by balancing the bromine atoms first, then balance the chlorine atoms. In this case, you would need to put a coefficient of 2 in front of BrCl and Cl2 to balance the equation, giving you the balanced equation: 2BrCl → Cl2 + Br2.
In the reaction Mg plus Cl2 MgCl2 what should be the coefficient for Cl2?
1
How many moles K are needed to react with 15 moles of Cl2?
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
Does a beta particle have a -2 charge?
no its charge is -1
What is the charge on Cl in the compound Cl2?
-1, and since there is two, -2.
What is the charge of cholrine?
Chlorine has a charge of -1 when it forms an ion by gaining an electron to achieve a full outer electron shell.
What is the charge on chlorine in the compound chlorine 2?
In the compound Cl2, each chlorine atom has a charge of 0 because chlorine is a diatomic molecule composed of two chlorine atoms sharing electrons equally (nonpolar covalent bond).
Which has the greater number of atoms 1 molecule of Cl2 or 1 molecule of P4?
1 molecule of Cl2 has 2 atoms, while 1 molecule of P4 has 4 atoms. Therefore, 1 molecule of P4 has a greater number of atoms.
How many grams of NaCl will be produced from 13g Cl2?
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
What is he necessary amount of chlorine needed to prepare 25.00 g of hydrogen chloride by reacting hydrogen with chlorine?
H2 (g) + Cl2 (g) --> 2 HCl (g) 25.00 g HCl x 1 mol HCl x 1 mol Cl2 x 70.90 g Cl2 = 24.3 g Cl2 are needed. ................... 36.46 g HCl . 2 mol HCl .. 1 mol Cl2
What is the symbol of the cation in Fe Cl2 formula?
The symbol for the cation (positive ion) is Fe2+. This is because that each Chlorine atom has a charge of -1 so to make the ions charge 0 overall, Fe must be 2+. Hope this helps!
What is the chemical equation for magnesium plus chlorine?
Magnesium has a charge of +2 and Chloride has a charge of -1. In order to make magnesium chloride have a net charge of zero, there must be twice as much of the chloride ion than the magnesium ion. The ratio of magnesium to chloride is therefore 1:2. With this knowledge, we can write the chemical equation MgCl2.
What charge is chlorine?
Chlorine is a negatively charged ion, known as chloride (Cl-).
What is the ratio of Cl2 to Mg in MgCl2 if you have 0.03mol Mg and 0.06mol Cl2?
The balanced chemical equation for the reaction between Mg and Cl2 to form MgCl2 is: Mg + Cl2 -> MgCl2 From the equation, it can be seen that 1 mol of Mg reacts with 1 mol of Cl2 to produce 1 mol of MgCl2. Therefore, the ratio of Cl2 to Mg in MgCl2 would be 1:1.
How do you balance BrCl --- Cl2 plus Br2?
To balance the chemical equation BrCl → Cl2 + Br2, you need to make sure that there are the same number of atoms of each element on both sides of the equation. Start by balancing the bromine atoms first, then balance the chlorine atoms. In this case, you would need to put a coefficient of 2 in front of BrCl and Cl2 to balance the equation, giving you the balanced equation: 2BrCl → Cl2 + Br2.
Given that 31.6ml of 0.141M Na2S2O3 is needed to reach the stoichiometric point how many grams of Cl2 are in the titrated?
Thiosulfate: 2 S2O32- --> S4O62- + 2e-equivalency to:Chlorine: 1 Cl2 + 2e- --> 2Cl-31.6 ml * 0.141 mmol/ml S2O32- = 4.456 mmol S2O32-= 4.456 *(2 electron / 2 S2O32-) = 4.456 mmol (electrons) == 4.456 *(1 Cl2 / 2 electron) = 2.228 mmol Cl2 == 2.228 * 70.90 mg/mmol Cl2 = 158 mg == 0.158 g Chlorine
