None of the above. It is only a place to connect to the power grid. There is a bit more to the answer than this, but here it is. There is voltage at the outlet. Voltage is the ability to move electrons (current). What you plug in has "resistance" to it. It (the appliance) is designed to work at that voltage, so it has an amount of "resistance" associated with it owing to its construction. The combination of the voltage present and the "resistance" plugged into the voltage source will determine the amount of current that will be drawn. The fundamental relationship between voltage, resistance and current is that voltage (which is electromotive force and will cause current to flow if given a complete circuit to work through) equals current (the actual moving electrons, or the amount of moving electrons) times resistance (the limiting factor in things - the nature of the material in the circuit and the configuration of the material as regards how well it will conduct electric current that is changing direction, is alternating). Breakers or fuses in the distribution panel provide a current limiting safety feature. But the electrical outlet itself controls nothing that is plugged into it. In the power grid, the voltage is AC (alternating current), and a lot of the things we plug in are inductive (like electric motors) and not "resistive" as stated above. The term "resistive" was used to convey basic meaning. This is a basic question. Don't trash this answer with a lot of highly technical mumbo jumbo. Save that for the engineering section. See you there.
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∙ 15y agoA wall outlet controls voltage by providing a constant voltage level (usually around 120V in the US) for devices to operate. The resistance of a device determines how much current flows through it based on Ohm's law (V=IR), but the outlet itself does not directly control resistance.
The voltage drop across the wiring in the wall is calculated using Ohm's Law: V = I * R, where V is the voltage drop, I is the current, and R is the resistance. Plugging in the values, V = 10 A * 0.12 ohms = 1.2 V. Therefore, the voltage drop across the wiring in the wall is 1.2 V.
If you plug a 110-v toaster into a 220-v outlet, the current flowing through the toaster will double since the voltage has doubled. This increased current can damage the toaster and cause it to overheat or even catch fire. It is essential to use electrical appliances only with the correct voltage to prevent accidents and damage to the devices.
No, plugging a 240V appliance into a 220V outlet may cause the appliance to not work properly or even damage it, as it is not getting the required voltage. It is important to match the voltage requirements of the appliance with the outlet to avoid potential safety hazards.
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
Electricity still flows through the wiring in a circuit even if nothing is plugged into the outlet, but it won't be powering any devices. The flow of electricity is not dependent on whether something is plugged in or not.
Ohm's Law says Voltage = Current x Resistance V = 5 x 24 = 120 V.
We know that Voltage = Current x Resistance, so if E = I x R, then E = 20 x 12 = 240 volts, and the dryer must be plugged into a 240 volt outlet.
The voltage drop across the wiring in the wall is calculated using Ohm's Law: V = I * R, where V is the voltage drop, I is the current, and R is the resistance. Plugging in the values, V = 10 A * 0.12 ohms = 1.2 V. Therefore, the voltage drop across the wiring in the wall is 1.2 V.
If you plug a 110-v toaster into a 220-v outlet, the current flowing through the toaster will double since the voltage has doubled. This increased current can damage the toaster and cause it to overheat or even catch fire. It is essential to use electrical appliances only with the correct voltage to prevent accidents and damage to the devices.
The formula you are looking for is V = IR where V = Voltage I = Current R = Resistance With some formula manipulation and numbers plugged in you get I = 120V / 9.6Ω I = 12.5A The kettle would have 12.5 volts of current running through it.
Current = (voltage) / (resistance) = 100/130 = 0.769 A = 769 milliamperes (rounded)
To find the resistance in a circuit, use the equation R = V/I, where R is the resistence in ohms, V is the voltage, and I is the current in amps. Therefore, your equation is R = 120/0.6. Therefore, the resistance is 200 ohms. Hope this helps
Electricity is transferred with high voltage and low current to reduce transmission loss ( I2R , where R= resistance of wire). As high voltage is present in transmission lines, Danger-high voltage is written.
AC welders use electric voltage directly from an alternating current outlet.
Is this, intentionally, a trick question?We are dealing with alternating current, here, not direct current. So, if you divide the supply voltage by the current drawn by the television set, you are determining its impedance(Z), not its resistance:Z = V/I = 120/3 = 40 ohmsImpedance is the vector sum of resistance and reactance. As the current is probably being drawn by a transformer, the resistance will be significantly lower than the reactance, perhaps only an ohm or two -if that!So, from the information supplied, you cannot determine the resistance.
Power (Watts) = Current (Amps) * VoltagePower = 22Amps * 240 VoltsPower = 5,280 Watts5280
An outlet that is at voltage. A dead outlet will not have zero voltage, thus cannot provide power.