None of the above. It is only a place to connect to the power grid. There is a bit more to the answer than this, but here it is. There is voltage at the outlet. Voltage is the ability to move electrons (current). What you plug in has "resistance" to it. It (the appliance) is designed to work at that voltage, so it has an amount of "resistance" associated with it owing to its construction. The combination of the voltage present and the "resistance" plugged into the voltage source will determine the amount of current that will be drawn. The fundamental relationship between voltage, resistance and current is that voltage (which is electromotive force and will cause current to flow if given a complete circuit to work through) equals current (the actual moving electrons, or the amount of moving electrons) times resistance (the limiting factor in things - the nature of the material in the circuit and the configuration of the material as regards how well it will conduct electric current that is changing direction, is alternating). Breakers or fuses in the distribution panel provide a current limiting safety feature. But the electrical outlet itself controls nothing that is plugged into it. In the power grid, the voltage is AC (alternating current), and a lot of the things we plug in are inductive (like electric motors) and not "resistive" as stated above. The term "resistive" was used to convey basic meaning. This is a basic question. Don't trash this answer with a lot of highly technical mumbo jumbo. Save that for the engineering section. See you there.
The voltage drop across the wiring in the wall is calculated using Ohm's Law: V = I * R, where V is the voltage drop, I is the current, and R is the resistance. Plugging in the values, V = 10 A * 0.12 ohms = 1.2 V. Therefore, the voltage drop across the wiring in the wall is 1.2 V.
It doesnt matter you will smoke it. The current in a resistive circuit is proportional to the voltage. If the voltage doubles and the resistance is the same (elements) the current will double and burn up both the elements and the toaster wiring. Look up "ohms law" for current voltage and resistance effects. Don't try it..
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
No, plugging a 240V appliance into a 220V outlet may cause the appliance to not work properly or even damage it, as it is not getting the required voltage. It is important to match the voltage requirements of the appliance with the outlet to avoid potential safety hazards.
Yes. If you hook up your phone charger, it is using a little bit over 50% power without a phone attached. No. The voltage potential of 120 volts is at the receptacle outlet slots but to make the current flow, a resistive load is needed. In the case above the phone charger is the load. Un-plug the load and no current flow.
Ohm's Law says Voltage = Current x Resistance V = 5 x 24 = 120 V.
We know that Voltage = Current x Resistance, so if E = I x R, then E = 20 x 12 = 240 volts, and the dryer must be plugged into a 240 volt outlet.
The voltage drop across the wiring in the wall is calculated using Ohm's Law: V = I * R, where V is the voltage drop, I is the current, and R is the resistance. Plugging in the values, V = 10 A * 0.12 ohms = 1.2 V. Therefore, the voltage drop across the wiring in the wall is 1.2 V.
It doesnt matter you will smoke it. The current in a resistive circuit is proportional to the voltage. If the voltage doubles and the resistance is the same (elements) the current will double and burn up both the elements and the toaster wiring. Look up "ohms law" for current voltage and resistance effects. Don't try it..
The formula you are looking for is V = IR where V = Voltage I = Current R = Resistance With some formula manipulation and numbers plugged in you get I = 120V / 9.6Ω I = 12.5A The kettle would have 12.5 volts of current running through it.
Current = (voltage) / (resistance) = 100/130 = 0.769 A = 769 milliamperes (rounded)
Electricity is transferred with high voltage and low current to reduce transmission loss ( I2R , where R= resistance of wire). As high voltage is present in transmission lines, Danger-high voltage is written.
To find the resistance in a circuit, use the equation R = V/I, where R is the resistence in ohms, V is the voltage, and I is the current in amps. Therefore, your equation is R = 120/0.6. Therefore, the resistance is 200 ohms. Hope this helps
AC welders use electric voltage directly from an alternating current outlet.
An outlet that is at voltage. A dead outlet will not have zero voltage, thus cannot provide power.
Is this, intentionally, a trick question?We are dealing with alternating current, here, not direct current. So, if you divide the supply voltage by the current drawn by the television set, you are determining its impedance(Z), not its resistance:Z = V/I = 120/3 = 40 ohmsImpedance is the vector sum of resistance and reactance. As the current is probably being drawn by a transformer, the resistance will be significantly lower than the reactance, perhaps only an ohm or two -if that!So, from the information supplied, you cannot determine the resistance.
Power (Watts) = Current (Amps) * VoltagePower = 22Amps * 240 VoltsPower = 5,280 Watts5280