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The latent heat of fusion for ice is 144 BTU/lb. For one ton, that is 2000 lb x 144 BTU/lb, or 288,000 BTU. Refrigeration's roots are in the ice making industry, and the ice guys wanted to convert this into ice production. If 288,000 BTU are required to make one ton of ice, divide this by 24 hours to get 12,000 BTU/Hr required to make one ton of ice in one day.

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Yes, one ton of ice is equivalent to 12000 British Thermal Units (BTU). This unit of measure is commonly used in the air conditioning and refrigeration industry to indicate cooling capacity.

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Q: Does one ton of ice equal 12000 btu?
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How many btu in one cubic meter?

Btu and cubic meter are two different measuring units. Btu is the unit for heat transmission, like in ac units 12000 btu/hr. It means this ac unit would remove 12000 btu of heat from the room in one hour. where as cubic meter is the unit for volume.


How many BTU to melt one ton of ice in 24hrs?

It would take approximately 12,000 BTU (British Thermal Units) to melt one ton (2000 pounds) of ice in 24 hours. This is based on the heat of fusion of ice, which is 144 BTU per pound.


How many sq feet does a 2 ton unit cover?

Ton for air conditioner1 ton of air conditioning = 12,000btu`s of cooling per 1 hour. 2 ton = 24,000 btu`s of heat removed in 1 one hour3 ton - 36,000 and so on.Airflow is measured in CFM (cubic feet per minute)


Converting therms to btu?

To convert therms to BTU, you can use the conversion factor: 1 therm = 100,000 BTU. Simply multiply the number of therms by 100,000 to get the equivalent number of BTU.


How many btu must be removed from one pound of water at 200F for it to end as ice at 30F?

To calculate the heat energy required to cool water from 200°F to 32°F (its freezing point) and then to further cool it to 30°F and freeze it, we need to consider the specific heat capacities and latent heat of fusion of water. The specific heat capacity of water is 1 BTU/lb°F, and the latent heat of fusion of water is 144 BTU/lb. To cool water from 200°F to 32°F, we need to remove: (200°F - 32°F) * 1 BTU/lb°F = 168 BTU. To freeze the water at 32°F, we need to remove the latent heat of fusion: 144 BTU. Therefore, the total heat energy required to cool one pound of water from 200°F to ice at 30°F is 168 BTU + 144 BTU = 312 BTU.