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9*11 = 9*(10 + 1) = 9*10 + 9*1 = 9*10 + 9.

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Explain how to find the distance traveled in centimeters if it was 15 millimeters?

1.5 cm 1 cm = 10 mm 1 mm = 0.1 cm


When an aqueous solution at room temperature is analyzed the H is found to be 2.0 103 M. What is the OH?

To find the hydroxide ion concentration ([OH^-]) in an aqueous solution, you can use the relationship given by the ion product of water at room temperature, (K_w = [H^+][OH^-] = 1.0 \times 10^{-14}) at 25°C. Given that ([H^+] = 2.0 \times 10^{-3} , M), you can rearrange the equation to find ([OH^-]): [ [OH^-] = \frac{K_w}{[H^+]} = \frac{1.0 \times 10^{-14}}{2.0 \times 10^{-3}} = 5.0 \times 10^{-12} , M. ] Thus, the hydroxide ion concentration is (5.0 \times 10^{-12} , M).


How many moles are in 8.5x1025 moles of co2?

The notation (8.5 \times 10^{25}) refers to a quantity of molecules, not moles. To convert molecules to moles, divide by Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules/mole. Thus, to find the number of moles in (8.5 \times 10^{25}) molecules of CO2, divide (8.5 \times 10^{25}) by (6.022 \times 10^{23}), resulting in approximately 141.5 moles of CO2.


How many moles of nickel atoms are there in 8.00 x 109 Ni atoms?

To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.


How many moles are in 1.63x10 to the 24th atoms?

To find the number of moles in (1.63 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Divide the number of atoms by Avogadro's number: [ \text{moles} = \frac{1.63 \times 10^{24}}{6.022 \times 10^{23}} \approx 2.71 \text{ moles}. ] Thus, there are approximately 2.71 moles in (1.63 \times 10^{24}) atoms.

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