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9*11 = 9*(10 + 1) = 9*10 + 9*1 = 9*10 + 9.

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An earthquake registered 7.4 on the Richter scale. If the reference intensity of this quake was 2.0 and times 1011 what was its intensity?

To find the intensity of an earthquake based on its Richter scale magnitude, you can use the formula: [ I = I_0 \times 10^{(M)} ] where (I_0) is the reference intensity and (M) is the magnitude. For a magnitude of 7.4 and a reference intensity of (2.0 \times 10^{11}), the intensity (I) can be calculated as follows: [ I = 2.0 \times 10^{11} \times 10^{7.4} = 2.0 \times 10^{11} \times 2.511886431 = 5.023772862 \times 10^{11} ] Thus, the intensity of the earthquake is approximately (5.02 \times 10^{11}).


Explain how to find the distance traveled in centimeters if it was 15 millimeters?

1.5 cm 1 cm = 10 mm 1 mm = 0.1 cm


When an aqueous solution at room temperature is analyzed the H is found to be 2.0 103 M. What is the OH?

To find the hydroxide ion concentration ([OH^-]) in an aqueous solution, you can use the relationship given by the ion product of water at room temperature, (K_w = [H^+][OH^-] = 1.0 \times 10^{-14}) at 25°C. Given that ([H^+] = 2.0 \times 10^{-3} , M), you can rearrange the equation to find ([OH^-]): [ [OH^-] = \frac{K_w}{[H^+]} = \frac{1.0 \times 10^{-14}}{2.0 \times 10^{-3}} = 5.0 \times 10^{-12} , M. ] Thus, the hydroxide ion concentration is (5.0 \times 10^{-12} , M).


How many moles are in 8.5x1025 moles of co2?

The notation (8.5 \times 10^{25}) refers to a quantity of molecules, not moles. To convert molecules to moles, divide by Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules/mole. Thus, to find the number of moles in (8.5 \times 10^{25}) molecules of CO2, divide (8.5 \times 10^{25}) by (6.022 \times 10^{23}), resulting in approximately 141.5 moles of CO2.


How many moles of nickel atoms are there in 8.00 x 109 Ni atoms?

To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.

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10 multiplied by 147 is 1,470.


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What is 0.4 is 10 times as much as what?

To find what 0.4 is 10 times as much as, you can divide 0.4 by 10. This calculation gives you 0.04. Therefore, 0.4 is 10 times as much as 0.04.


What times 10 equals 100000000000?

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