Yes.
To balance the combustion reaction of C5H12 + O2 → CO2 + H2O, first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation is: C5H12 + 8 O2 → 5 CO2 + 6 H2O
To balance the equation for the reaction of C10H22 (decane) with C6H14 (hexane) and C2H4 (ethylene), you first need to identify the products, typically carbon dioxide (CO2) and water (H2O) if combustion is assumed. However, without specific conditions or products mentioned, it’s unclear how to balance this reaction properly. Please clarify the context or type of reaction for a precise balancing.
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
When hexane (C6H14) reacts with oxygen gas (O2) in the presence of heat or a spark, combustion occurs producing carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for this reaction is: 2 C6H14 + 19 O2 -> 12 CO2 + 14 H2O.
To balance the combustion reaction of C5H12 + O2 → CO2 + H2O, first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation is: C5H12 + 8 O2 → 5 CO2 + 6 H2O
C6h14 + 13o2 ---> 7h2o + 6co2 The website keeps making correctinos to my capitalization of the elements, but this is the balanced equation.
The answer is 26,8 mg CO2.
To balance the equation C6H12 + O2 → CO2 + H2O, first balance the carbon atoms by putting a coefficient of 6 in front of CO2. Then balance the hydrogen atoms by putting a coefficient of 6 in front of H2O. Finally, balance the oxygen atoms by putting a coefficient of 9 in front of O2. The balanced equation is: C6H12 + 9O2 → 6CO2 + 6H2O
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
The balanced chemical equation for the reaction of barium bicarbonate (Ba(HCO3)2) is: Ba(HCO3)2 → BaCO3 + CO2 + H2O This reaction results in the formation of barium carbonate (BaCO3), carbon dioxide (CO2), and water (H2O).