The balanced reaction is this: 2CO + O2 --> 2CO2
This is correct...
the correct way of balancing this is:
CO+ 1/2O2 --> CO2
if you're using the above method to calculate enthalpy value then they will be different (and incorrect) compared to balancing it this way.
To balance the combustion reaction of C5H12 + O2 → CO2 + H2O, first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation is: C5H12 + 8 O2 → 5 CO2 + 6 H2O
To balance the combustion reaction of pentane (C5H12) with oxygen (O2) yielding carbon monoxide (CO) and water (H2O), start by writing the unbalanced equation: C5H12 + O2 → CO + H2O. Balance the carbon atoms by placing a coefficient of 5 in front of CO, and balance the hydrogen by placing a coefficient of 6 in front of H2O. Finally, balance the oxygen atoms by calculating the total oxygen needed on the right side (5 from CO and 6 from H2O, totaling 11), and adjust the coefficient for O2 accordingly to 11/2, or 5.5. The final balanced equation is: C5H12 + 5.5 O2 → 5 CO + 6 H2O.
the chemical equation CO2 C--CO.it is balANCEd by :there are 2 carbons on reactants and 2 atoms of oxygen by putting 2 as coeffecient on product side,equationis balanced.CO2 + C --------> 2CO
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
To balance the equation C + O2 → CO, you need to add a coefficient of 2 in front of CO. This balances the equation so that you have the same number of carbon and oxygen atoms on both sides: C + O2 → 2CO.
The equilibrium constant for the reaction C + O2 -> CO is Kc = [CO]/([C][O2]), where the square brackets denote molar concentrations.
To balance the combustion reaction of C5H12 + O2 → CO2 + H2O, first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation is: C5H12 + 8 O2 → 5 CO2 + 6 H2O
the chemical equation CO2 C--CO.it is balANCEd by :there are 2 carbons on reactants and 2 atoms of oxygen by putting 2 as coeffecient on product side,equationis balanced.CO2 + C --------> 2CO
2CO + O2 --> 2CO2
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
C + 1/2 O2 ----> CO ------> mole basis 12 C + 16 O2 ----> 28 CO -----> mass basis CO made = ( 36 g C ) ( 28 g CO / 12 g C ) = 84 g CO <-----------------
The balanced equation for the conversion of carbon dioxide (CO2) to carbon monoxide (CO) is: 2CO2 → 2CO + O2
The chemical equation for the gasification of coal can be represented as: C + H2O -> CO + H2
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
To balance the equation C + O2 -> CO2, you need to ensure that there are the same number of atoms for each element on both sides of the equation. In this case, you would need to add a coefficient of 2 in front of CO2: C + O2 -> 2CO2. This balances the equation with one carbon atom and two oxygen molecules on each side.
2 C + O2 -> 2 CO.