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C1v1=c2v2

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To convert DNA with a concentration of 660.92 ng/uL to 5000 ng/uL in a total volume of 25 uL, you can calculate the volume of the original DNA required to reach the desired concentration. First, determine the amount of DNA needed in the final concentration (5000 ng/uL * 25 uL = 125,000 ng). Then, divide this amount by the original concentration to find the volume required (125,000 ng / 660.92 ng/uL ≈ 189.14 uL). Therefore, you would mix the original DNA with an appropriate volume of diluent to reach the desired concentration and then adjust the total volume to 25 uL.

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Q: How do you convert DNA with a concentration of 660.92 ng per uL to 5000 ng per uL and end up with a total volume of 25uL?
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To calculate the concentration in ppm, you need to know the mass of the chemical added to the water. If you know the density of the chemical, you can convert the volume (4 mL) to mass. Then, you can calculate the concentration in ppm using the mass of the chemical and the total volume of the solution (1 liter).


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Why molarity not based on the volume of solvent alone?

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What is 4 ml of chemical added to 1liter of water in many ppm concentration?

To calculate the concentration in ppm, you need to know the mass of the chemical added to the water. If you know the density of the chemical, you can convert the volume (4 mL) to mass. Then, you can calculate the concentration in ppm using the mass of the chemical and the total volume of the solution (1 liter).


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What is the volume percent concentration of hexadecimal in a solution made by mixing 50.0 ml of hexadecimal with 1.0 like of pentane?

To calculate the volume percent concentration of a component in a solution, you need to know the total volume of the solution. In this case, the total volume after mixing would be 50.0 ml + 1.0 ml = 51.0 ml. To find the volume percent of hexadecimal, you would take the volume of hexadecimal (50.0 ml) divided by the total volume of the solution (51.0 ml) and multiply by 100. This gives you a volume percent concentration of hexadecimal in the solution.


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