Dissolve 0.01 mole 1) methformin, C4H11N5 in some milllilitrers dilute HCl and when dissolved add up to 10 ml.
1) Be aware that methformin is only soluble as hydrochloric salt ( C4H11N5.HCl ).
So you should correct for the real molacular mass: 129.164 g/mol (C4H11N5) compared to 165.63 g/mol for C4H11N5.HCl if you are weighting the salt in stead of the pure methformin.
Calcium sulfate is very low soluble in water - 2,1 g/L at 20 0C.
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
The term molar it refers a form to know the concentration of a solution, and it is equivalent to a molar unit in a litre of solvent 1 Molar (1M) = 1 mole (molecular weight from the structure you are interested in) / 1000 mL or 1 L. Milimolar is the thousandth part from a solution 1M
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
To make a 1 molar solution of glucose (C6H12O6) in 1 liter of water, you would need to dissolve 180 grams of glucose. This is because the molar mass of glucose is 180 g/mol, so 1 mole of glucose weighs 180 grams.
Calcium sulfate is very low soluble in water - 2,1 g/L at 20 0C.
To make a 0.1 molar solution from a 1.0 molar solution, you would dilute the original solution by a factor of 10. For example, you could mix 1 part of the 1.0 molar solution with 9 parts of solvent (like water) to achieve a final concentration of 0.1 molar.
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
6.023 X 1023 particles make up a 1M solution.
To make a molar solution from a 32% hydrochloric acid solution, you would need to first calculate the molarity of the 32% solution. Molarity is calculated by multiplying the percent concentration by the density of the solution and dividing by the molar mass of the solute. Once you determine the molarity, you can then dilute the solution to the desired molar concentration by adding the appropriate amount of solvent (usually water).
To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.
To make a molar solution, you need to dissolve the appropriate amount of a substance in a specific volume of solvent to achieve a certain concentration measured in moles per liter. This involves calculating the molar mass of the substance and using the formula C n/V, where C is the concentration, n is the number of moles of the substance, and V is the volume of the solution.
To make a 1 molar solution of sodium azide, you would need to dissolve 65.01 g of sodium azide in water to make 1 liter of solution. Since you have 98 mg of sodium azide, you would need to add enough water to make a final volume of 1 liter to create the 1 molar solution.
yes
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
20 ml
The term molar it refers a form to know the concentration of a solution, and it is equivalent to a molar unit in a litre of solvent 1 Molar (1M) = 1 mole (molecular weight from the structure you are interested in) / 1000 mL or 1 L. Milimolar is the thousandth part from a solution 1M