To calculate it find the volume of the sand in the container and multiply this by the density of the sand in the container.
A much easier way to find the mass of the sand is to weight the container with the sand in it, empty the sand out of the container (and into another container if you want to keep the sand), re-weight the now empty container and subtract this weight from the first.
Depends on how much and what aspect.
Cubic kilometres for the volume of sand in a desert;
Cubic metres for the volume on a small beach;
Cubic centimetres for the volume in a child's bucket;
Tons for the mass of large volumes,
Kilograms for smaller volumes;
Grams for small volumes;
Micrometres for the fineness of the grains;
Then there are measures of reflectivity, etc.
To determine the mass of the sand, you'll need to subtract the mass of the container (14.5 grams) from the total mass of the container with sand in it. For example, if the total mass of the container with sand is 50 grams, then the mass of the sand would be 50 grams - 14.5 grams = 35.5 grams.
You can use filtration to separate sand from a mixture in a beaker. Simply pour the mixture through a filter paper in a funnel set over another beaker. The sand will be left behind in the filter paper while the other components of the mixture pass through.
what is used to measure dry sand
When you add water to sand, the volume and mass of the mixture will increase. The density of the mixture will depend on the ratio of sand to water added, but generally, the density will be lower than that of pure sand due to the lower density of water compared to sand.
A beaker containing sand and water is a mixture because it contains two or more different substances physically intermingled. Sand itself is a pure substance because it is made up of only one type of particle. When sand is added to water in a beaker, they do not chemically combine, so it remains a mixture.
You can weigh it.
To determine the mass of the sand, you'll need to subtract the mass of the container (14.5 grams) from the total mass of the container with sand in it. For example, if the total mass of the container with sand is 50 grams, then the mass of the sand would be 50 grams - 14.5 grams = 35.5 grams.
Because you mixed sand and water together in the beaker.
I assume the salt is the table salt type -- inactive. If true, the salt just dissolves and no chemical reaction results or heat generated. The mass will be the sum of that of the salt and water. Ans = 123 g.
The total mass of the container and sand is 167.5g (100g + 60g + 7.5g).
Letting the sand settle at the bottom of the beaker helps separate it from the solution, reducing the risk of contaminating the solution with sand particles. This step allows for cleaner and more accurate transfer of the solution into another beaker for further processing or analysis.
Pour the sand, salt, water mixture through a filter into beaker 1. The sand will be left behind. Pour this into beaker 2. Evaporate the liquid, condensing the vapor into beaker 3. This will be pure water, leaving the salt in beaker 2.
To find the density of sand, measure the mass of a given volume of sand using a balance, then divide the mass by the volume. The density of sand can vary depending on its composition and particle size, but typically falls between 1.5 to 2.7 grams per cubic centimeter.
You can use filtration to separate sand from a mixture in a beaker. Simply pour the mixture through a filter paper in a funnel set over another beaker. The sand will be left behind in the filter paper while the other components of the mixture pass through.
what is used to measure dry sand
Add water to the mixture to dissolve the copper sulfate. Filter the mixture to separate the sand from the copper sulfate solution. Evaporate the water from the solution to recover the copper sulfate.
There can be no equivalence. A ton of sand represents the mass of a volume of sand. The volume is a 3-dimensional measure whereas a metre is a measure of length or distance in 1-dimensional space. According to basic rules of dimensional analysis, any attempt at conversion from volume to length is fundamentally flawed.