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Well if1cm=1g obviously that is the answer like800cm=800gThis is what I learnt in math today but I'm not very good so ye I think its Right :D
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Wiki User

13y ago
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Anonymous

Lvl 1
3y ago
1ml of water equals 1g, not 1cm of a random material
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AnswerBot

3w ago

On average, 1 cm of ginger weighs approximately 2 grams. This can vary slightly based on the size and density of the ginger piece.

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Q: How heavy is 1 cm of ginger in grams?
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Continue Learning about Natural Sciences

How many grams in a 1 liter?

mass = volume * density Grams are a measure of mass. Liters are a measure of volume. You can use the internet to look up the density for the gas to which you are referring. For instance, hydrogen's density is .0000899 g/cm^3 (grams per cubic centimeters). One liter is 1000 cm^3. 1000 cm^3 * .0000899 g/cm^3 = 0.0899 g Therefore a liter of hydrogen contains about 0.09 grams of hydrogen.


How much deuterium is in one litter of heavy water?

One liter of heavy water contains approximately 11 grams of deuterium.


What is the specific gravity of a mineral that weighs 27 grams and takes up 10.4 cubic cm of space?

It would be 2.596. Take the density in grams divided by its volume. So, 27 grams divided by 10.4 cubic cm= 2.56 g/cubic cm which would then be divided by the density of water, which is 1 g/ cubic cm, and the g/ cubic cm cancels out, leaving the answer as 2.596 without a unit. Hope that helps.


If the density of seawater is 1 and four hundredths grams per centimeter cubed what is the mass of 1000 centimeter cubed of sea water?

The mass of 1000 cm^3 of seawater can be calculated by multiplying its density (1.04 g/cm^3) with the volume (1000 cm^3). Mass = Density x Volume Mass = 1.04 g/cm^3 x 1000 cm^3 Mass = 1040 grams Therefore, the mass of 1000 cm^3 of seawater is 1040 grams.


How many grams are in 1 liter of water?

In short? 1 kg. But more accurately, it depends on the temperature. Room temperature, (23 C) has a density of .997 g/cm^3, and 1 cm^3 of water is 1 mL. So, in 1 Liter, there would be 997 g, or .997 kg.