25/1.5=16.67 times approx.
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5/6 of 30L is 25L
303K refers to a temperature of 303 Kelvin, which is equivalent to approximately 30 degrees Celsius. "Volume at 25L" typically means the volume of a substance is 25 liters, indicating the amount of space that substance occupies.
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Using the ideal gas law, V1/T1 = V2/T2. Plugging in the values, 25L/288K = V2/303K. Solving for V2 gives V2 = (25 L * 303 K) / 288 K = 26.39 L. The gas will occupy a volume of 26.39 L when the temperature is increased to 303 K.
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