The circuit will have zero amps. There is one value missing from the question. The equation that you are looking for is I = E/R. Amps = Volts/Resistance or I = W/E or I = Sq Root of W/R.
Once you find the resistance or watts, using the equations above you can find the amperage the circuit draws.
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A 110-volt circuit can typically carry up to 15-20 amps of current, depending on the wiring and circuit breaker used. It is important to check the specific rating of the circuit to ensure it can safely handle the connected load.
110 is commonly used to refer to the 120 volt, 60Hz electrical service found in the US and Canada. The current (measured in amperes or amps) is not related to the voltage so the answer is it cannot be determined. The amount of current that can be safely used in a circuit is determined by several factors, mainly the size and length of the connecting wire and the rating of the protection device (fuse or circuit breaker).
Most 120V household wall receptacles are rated at 15 amps.
Voltage is a potential. Current is actual consumption of that potential. Current times voltage is power.
You can not make any assumption of power from voltage.
The amperage in the circuit can be calculated using Ohm's Law: Amperage = Voltage / Resistance. Plugging in the values, we get Amperage = 110V / 7ohms = 15.71A. Therefore, the circuit would have approximately 15.71 amps of current flowing through it.
It depends on the capacity of the circuit. A typical residential circuit in the US is rated for 15 or 20 amps.
To calculate the amps, you can use the formula: Amps = Watts / Volts. So, for 2000 watts and 110 volts, 2000 watts / 110 volts equals approximately 18.18 amps.
To find the amperage, you can use the formula: Amps = Watts/Volts. Plugging in the values, you get Amps = 1800 Watts / 110 Volts ≈ 16.36 Amps.
To calculate the amperage, use the formula: Amps = Watts / Volts. In this case, 1700 watts / 110 volts = 15.45 amps. So, there are approximately 15.45 amps in 1700 watts on a 110-volt receptacle.