How many amps can be drawn from 10kw?

Answer 1

I believe that you can use as many watts as your generator is rated for. I was told that if you have a 5000 watt generator then you could use products whose watts added up to that amount. If you had a radio that used 100 watts, a heater that used 1200 watts, an electric blanket that used 1000 watts, a coffee pot that used 500 watts, and a left handed smoke shifter that used 2205 watts, you would have to wait to use the coffee pot until you weren't using something else because they all added up to 5005 watts. I believe that the same holds true for the amps. You need to know how many amps each item uses and do not go over that amount or you will blow a fuse. Look at the placard or manufacturers label on the items and it will give you their individual wattage and amphere ratings. p.s. Here's a little trivia for you. A Left Handed Smoke Shifter was an item that the newest scouts to the troop are given on a list to ask other scout camps for. There is no such thing. It was part of a scavenger hunt. watts=volts X amps ie 120v x 10a =1200watts

Answer 2

To calculate the amps drawn from 10kW, you need to know the voltage of the circuit. If the voltage is 120V, then the amperage would be 83.3A (10,000W ÷ 120V = 83.3A). If the voltage is 240V, then the amperage would be 41.7A (10,000W ÷ 240V = 41.7A).

Answer 3

You get watts by multiplying amps with volts, you do the math.

You have to know the voltage of the circuit in question before you can determine maximum wattage usage with a 10 amp circuit.

Let's say you're using a 115 volt AC source typically used in a house that has a 10 amp circuit breaker...using the formula P (power in watts) = I (current in amps) [10] x E (voltage) [115], you get:

P=115 volts x 10 amps,

P=1150 watts, which would be the maximum power consumption the circuit would be capable of handling before the circuit breaker trips..to equate that to a common modern appliance, 1150 watts is the typical power rating of most steam irons at their highest heat setting.

Answer 4

To answer this question the voltage is needed.